Tamil Nadu Agricultural University B.Tech cutoff 2024 is 45% aggregate marks or equivalent CGPA in 10 + 2. Moreover, candidates must have Mathematics, Physics, Chemistry and English as compulsory subjects in 10 + 2. Apart from that candidates who have applied to Tamil Nadu Agricultural University, must meet the cutoff or obtain a valid rank in JEE Main. Tamil Nadu Agricultural University B.Tech cutoff has not released officially. Meanwhile, candidates can have a look at the minimum cutoff of Tamil Nadu Agricultural University for courses like B.Tech in Agricultural Engineering, B.Tech. in Agricultural Information Technology, B. Tech. in Bioinformatics, B. Tech. in Biotechnology, B. Tech. in Energy and Environmental Engineering, B. Tech. in Food Technology, B.Tech. in Horticulture below:
Programme | 10+2 |
B.Tech in Agricultural Engineering | 45% marks in aggregate The students must have qualified their 12th board examinations with Physics, Chemistry, and Mathematics (PCM) or Physics, Chemistry and Biology (PCB). The candidates must have cleared their 12th from a recognized board. |
B. Tech. in Agricultural Information Technology | 45% marks in aggregate Candidates must complete their 10+2 in Science with Physics, Chemistry, Mathematics, and Biology from a recognised board. To apply to the course, candidates must appear for the JEE Main. |
B. Tech. in Bioinformatics | 45% marks in aggregate Candidates who have completed 10+2, in any of the Vocational Subjects (Basic Mechanical Engineering/ Basic Electrical Engineering/ Basic Electronics Engineering/ Basic Civil Engineering/ Basic Automobile Engineering/ Textile Technology) with any of the Engineering-related subjects, namely Mathematics. |
B. Tech. in Biotechnology | 45% marks in aggregate Candidates who have completed 10+2, in any of the Vocational Subjects (Basic Mechanical Engineering/ Basic Electrical Engineering/ Basic Electronics Engineering/ Basic Civil Engineering/ Basic Automobile Engineering/ Textile Technology) with any of the Engineering-related subjects, namely Mathematics. |
B. Tech. in Energy and Environmental Engineering | Applicants must meet the entry requirements - 45% in 12th |
B. Tech. in Food Technology | Candidate should have completed 10+2 having secured at least 45% in the aggregate from a recognized university. The candidate should have passed subjects like Physics, Chemistry and Mathematics. |
B.Tech. in Horticulture | The candidate must have completed HSC (10+2) or its equivalent with 45% from any recognised board/council. Candidates who have passed HSC, i.e., 10+2, in any of the Vocational Subjects (Basic Mechanical Engineering/ Basic Electrical Engineering/ Basic Electronics Engineering/ Basic Civil Engineering/ Basic Automobile Engineering/ Textile Technology) with any of the Engineering Related Subjects, namely Mathematics, Physics, or Chemistry, with the above-mentioned minimum average percentage combined are also eligible to apply. |
The table below shows the TNAU Coimbatore cutoff 2023 for several M.Sc. specialisations offered based on JNU CEEB 2023 entrance exam for students in various categories. For students in the general category, the TNAU M.Sc JNU CEEB cutoff 2023 is to range from 70 to 50 marks. Students of SC category might expect a cutoff of 50 to 40 marks. For ST category candidates, the ratio is 50 to 40 marks as well.
Category of candidates | Opening score | Closing score |
General | 70 | 50 |
SC | 50 | 40 |
ST | 50 | 40 |
BCM | 50 | 40 |
BC | 50 | 40 |
The TNAU UG cutoff 2022 is released on the official website by the university for the offered B.Sc as well as B.Tech courses. It is based on the merit of the candidates in the ICAR AIEEA UG entrance exam for the academic year 2022 for various category students. A minimum score of 183.33 marks was required for the general category students under the TNAU UG cut off 2022.
Category of candidate | Opening score | Closing score |
OC (General) | 187.5 | 183.33 |
BC | 187 | 172.94 |
MBC/ DNC | 196.5 | 191 |
SC | 165 | - |
The TNAU cutoff 2022 for the diploma courses has been released on the official website. The cutoff is generally based on the merit of the candidates for the academic year 2022 for various category students. Asper the TNAU Diploma cutoff 2022, candidates must have scored a minimum of 115.5 marks was required for the general category students.
Category of candidates | Opening score | Closing score |
OC (General) | 166 | 115.5 |
BC | 190.5 | 91 |
MBC/ DNC | 192.28 | 88.33 |
SC | 184 | 82.33 |
Bhubaneswar (Odisha)
Tindivanam (Tamil Nadu)
Thoothukudi (Tamil Nadu)
Tiruchirappalli (Tamil Nadu)