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School of Management Sciences (SMS), Lucknow Questions and Answers

LocationLucknow (Uttar Pradesh)
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Updated on - Dec 26, 2023 05:16 PM IST

Questions Asked On School of Management Sciences, Lucknow, Uttar Pradesh

D
Dewesh Nandan Prasad •  today

Dear Sir/Ma'am 

If your son has secured 91.21 percentile marks in JEE Mains 2025, then IIIT (Indian Institute of Information Technology) will offer admission for various engineering courses. Some of the IIITs that will offer admission are IIIT Allahabad, IIIT Gwalior, etc. However, to become eligible for the IIT (Indian Institute of Technology), he will have to appear for the JEE Advanced 2025 exam scheduled to be conducted on May 18, 2025, and as per the expected cut-off marks, he is eligible to appear for the JEE Advanced with a 91.21 percentile of marks in JEE Main 2025.

We hope that we have answered your query successfully. Stay tuned to CollegeDekho for the latest updates related to JEE Main Counselling and admissions. All the best for a good future, ahead!

D
Dewesh Nandan Prasad •  today

Dear Student,

With 91.5 percentile marks in JEE Main 2025, you can go to NIT Mizoram, NIT Jamshedpur, NIT Jalandhar, NIT Meghalaya, IIIT Allahabad, IIIT Gwalior, KIIT University, BIT Mesra, Lovely Professional University Jalandhar, etc. You can check the complete list of colleges with your secured percentile in JEE Main 2025 through the College Dekho College Predictor Tool, which is available for free.

We hope that we have answered your query successfully. Stay tuned to CollegeDekho for the latest updates related to JEE Main 2025 couselling, admission, and more.

D
Dewesh Nandan Prasad •  today

Dear Student,

Yes, you can get a Computer Science branch at the National Institute of Technology with 87 percentile marks in JEE Main 2025 in the Scheduled Tribe category.  The expected cut-off for NIT is around 75 percentile marks for the ST category in JEE Main 2025. We hope that we have answered your query successfully. Stay tuned to CollegeDekho for the latest updates related to JEE Main Counselling 2025, admission, and more. All the best for your future!

D
Dewesh Nandan Prasad •  today

Dear Student, 

If you have scored 80.66 percentile in JEE Main 2025, then you will get into colleges like the National Institute of Technology (NIT) Goa, NIT Mizoram, NIT Jamshedpur, NIT Jalandhar, NIT Meghalaya, IIIT Allahabad, IIIT Gwalior, KIIT University, BIT Mesra, Lovely Professional University Jalandhar, etc. You can check the complete list of colleges with your secured percentile in JEE Main 2025 through the College Dekho College Predictor Tool which is available for free. 

We hope that we have answered your query successfully. Stay tuned to CollegeDekho for the latest updates related to JEE Main 2025 couselling, admission, and more.

J
Jayita Ekka •  2 days ago

Dear student,

You are asking if the focal length of a lens is 20 cm, what is its power in diopters?

Calculating Lens Power:

  • Power of a lens is defined as the reciprocal of its focal length when expressed in meters
  • The unit of power of a lens is diopter (D)

Formula:

  • Power (P) = 1 / focal length (in meters)

Given:

  • Focal length (f) = 20 cm = 0.2 meters

Calculation:

  • Power (P) = 1 / 0.2 = 5 diopters

Therefore, the power of the lens is +5 diopters

Why is it positive?

  • A positive power indicates a convex lens (converging lens)
  • Convex lenses are thicker at the center and thinner at the edges
  • They converge light rays to a point called the focus

convex lens

Additional Notes:

  • Concave Lens: If the lens were concave (diverging lens), the power would be negative
  • Units: Always ensure that the focal length is converted to meters before calculating the power in diopters

Therefore, if a lens has a focal length of 20 cm, its power is +5 diopters. This means it is a convex lens capable of converging light rays.