NTA JEE Main Exam Pattern 2024 (Out) - Marking Scheme, Paper Pattern, Exam Mode & Duration

Updated By Diksha Sharma on 04 Apr, 2024 14:35

Predict your Percentile based on your JEE Main performance

Predict Now

JEE Main 2024 Exam Pattern

NTA has released the JEE Main Exam Pattern 2024 at jeemain.nta.ac.in. Students can check the detailed pattern in the information brochure available on the website. The JEE Main 2024 exam pattern contains information regarding the exam duration, exam mode, subjects, total marks marking scheme etc. As per the JEE Main 2024 exam pattern, Paper I (BE/B. Tech) consists of 90 questions with a total of 300 marks. The subjects included in JEE Main Paper 1 are Physics, Chemistry and Mathematics. Each section comprises 30 questions. Of these, 20 questions are MCQs and the remaining 10 are Numerical Answer Type (NAT). Candidates will have a choice of attempting 5 out of 10 questions in the JEE Main 2024 NAT section. Each question carries four marks. For every wrong answer, one mark will be deducted as a negative Marking in JEE Main 2024.

Paper 2 of JEE Mains (B.Arch) contains 82 questions from three sections - Mathematics (30 questions), Aptitude (50 questions), and Drawing (2 questions). The total marks allotted in this paper are 400. Except for the JEE Main 2024 Drawing Test section for B.Arch, both papers will be administered in CBT mode following the JEE Main Question Paper Pattern.

Note that the details of the exam centre will be mentioned in the JEE Main 2024 Hall Ticket.

The JEE Mains exam pattern 2024 is carefully designed to assess a candidate's knowledge, understanding and problem-solving skills in Physics, Chemistry and Mathematics. Candidates need to be familiar with the exam pattern and syllabus for JEE Mains 2024 before appearing for the exam to understand the type of questions asked in the exam and to improve their JEE Main 2024 preparation.

Q- What is the format of JEE Mains 2024?

Ans- The JEE Main 2024 Paper-1 consists of 90 questions in total, of which a candidate only needs to provide answers to 75 questions. There will be two sections for each subject. There will be 10 questions of the numerical value kind in Section B and 20 multiple-choice questions in Section A.

Q- What is the marking scheme for JEE Main 2024 BE/BTech paper?

Ans- JEE Main 2024 exam of BE/BTech paper will be held for a total of 300 marks. The candidate will be awarded 4 marks for each correct answer. 1 mark will be deducted for every wrong answer. There will be no mark deduction for unattempted questions. 

Q- Is JEE 2024 online or offline?

Ans- The JEE Main 2024 exam will be held online in Computer Based Test (CBT) mode.

Upcoming Engineering Exams :

Start Free Mock Test Now

Get real time exam experience with full length mock test and get detailed analysis.

Attempt now

JEE Main Latest Updates

JEE Main Exam Pattern 2024 of Paper 1 (B.E/B.Tech)

Students should be aware of the JEE Main 2024 Exam Pattern in order to understand the examination method, the type of questions asked, the total number of sections, the marking scheme, and so on. The JEE Main 2024 test pattern as per the previous trends is available in the table below.

Paper 1 (B.E/B.Tech) Exam Pattern

Particulars

Details

Mode of Exam

CBT (Computer-Based Test)

Exam Duration

3 hours/180 minutes

Language of Examination

English, Hindi, Marathi, Assamese, Tamil, Bengali, Kannada, Punjabi, Gujarati, Odia, Telugu, Malayalam and Urdu.

Type of Questions

  • Multiple choice questions (MCQs)
  • Questions with numerical responses

No. of Sections

Three are three sections:

  • Physics
  • Chemistry
  • Mathematics

No. of Questions

  • Mathematics: 25 (20+10) questions with numerical answers (five of the ten questions are required).
  • Physics: 25 (20+10) questions with numerical answers (five of the ten questions are required).
  • Chemistry: 25 (20+10) questions with numerical answers (five of the ten questions are required).

75 questions in total (25 questions each)

Total marks in JEE Mains

300 Marks (100 marks for each section)

JEE Main Marking Scheme

  • MCQs: Each correct answer will be worth four points, while each incorrect response will be worth one point.
  • Questions with numerical value answers: Candidates will receive four marks for each correct answer and one mark for each incorrect response.
  • There is no negative marking for unattempted questions

Q- What is the JEE Main 2024 exam pattern for Paper 1?

Ans- The three sections of JEE Main 2024 Paper 1 (B.E./B.Tech) are Physics, Chemistry, and Mathematics featuring Numerical-answer type Questions and Multiple Choice Questions (MCQs).

Q- Which is the easiest section to attempt in JEE Main 2024 paper 1 (BE/BTech)?

Ans- Chemistry is considered the easiest section in JEE Main 2024 paper 1 due to its theoretical and conceptual nature.

Q- What is the difficulty level of the JEE Main BE/BTech paper 1?

Ans- The difficulty level of the JEE Main BE/BTech paper differs as per the candidate’s preparation. Applicants who will study well will find the paper easy to solve. 

Quick Links:

JEE Main 2023 Question Paper PDF with Solutions

JEE Main 2022 Question Paper PDF with Solutions

JEE Main 2021 Question Paper PDF with Solutions

JEE Main 2020 Question Paper PDF with Solutions

JEE Main 2019 Question Paper PDF with Solutions

JEE Main 2018 Question Paper PDF with Solutions

JEE Main 2017 Question Paper PDF with Solutions

-

Colleges Accepting Exam JEE Main :

Tie Breaking Policy for JEE Main Paper I

If two or more candidates score the same marks in JEE Main Paper I exam, the order of merit will be determined as per the following tie-breaking rules. In order to give the candidates a detailed understanding of the tie-breaking policy, we have explained the same with some examples.

Tie Breaker 1: Candidates scoring higher marks in Mathematics will be given priority in the merit list as per tie-breaker policy - 1.

Example:

Let us assume that Candidate A and Candidate B have scored 280 out of 300 in JEE Main Paper I. However, Candidate A scored 80 marks in Mathematics, while Candidate B scored 82 in Mathematics. Here, Candidate B will be given priority in the merit list as per the Tie Breaker Policy 1.

Tie Breaker 2: This policy comes into effect only if two or more candidates score the same marks in Mathematics. Since two or more candidates have similar marks in Mathematics, the marks scored by candidates in Physics will be taken into consideration to determine the merit.

Example:

Let us assume that Candidate A and Candidate B have scored 280 out of 300 in JEE Main Paper I. Both of them have also scored 80 marks in Mathematics. However, Candidate A scored 85 in Physics and Candidate B scored 82 in Physics. As per the tie-breaker policy 2, Candidate A will be given higher preference in the merit list than Candidate B.

Tie Breaker 3: This policy comes into effect only if two or more candidates score similar marks in Physics. In such cases, marks scored by candidates in Chemistry will be taken into consideration to determine their merit.

Example:

Let us assume that Candidate A and Candidate B have scored 280 out of 300 marks in JEE Main Paper I. On the other hand, both these candidates scored the same marks in the Mathematics and Physics section of the exam. However, Candidate A scored 80 marks in Chemistry and Candidate B scored 81 marks. As per tie-breaker policy 3, Candidate B will be given a higher preference in the merit list than Candidate A.

Tie Breaker 4: This policy comes into effect only if two or more candidates score the same marks in the Mathematics, Physics and Chemistry sections of JEE Maine Paper I. In such cases, the candidate with less number of negative responses in the exam will be given higher preference in the order of merit.

Example:

Let us assume that Candidate A and Candidate B have scored 250 marks in JEE Main Paper I. On the other hand, both these candidates score the same marks in Mathematics, Physics and Chemistry. However, the number of wrong answers by Candidate A is 16, while the number of wrong answers by Candidate B is 18. In order to determine the merit, Candidate A will be given higher preference in the order of merit, as the number of wrong answers by Candidate A is less than Candidate B.

Tie Breaker 5: This policy comes into effect only if a tie still persists after applying all the above rules. In such cases, candidates older in age will be given higher preference in the merit list. Check the example below for a better understanding.

Example:

Let us assume that Candidate A and Candidate B scored 240 marks in JEE Main Paper I. On the other hand, these candidates scored the same marks in Mathematics, Physics and Chemistry. At the same time, the number of incorrect answers by these candidates is also the same. However, Candidate A is 17 years and 6 months old and Candidate B is 17 years and 8 months old. As per tie-breaker policy 5, Candidate B will be given higher preference in the merit list.

Q-  How does the Tie-Breaking Policy work in JEE Main 2024 Paper I?

Ans- In case two more candidates get the same JEE Main scores, the NTA employs the tie-breaking policy. As per the tie-breaking policy, a candidate with a higher Mathematic score will be given preference. If the tie still exists higher Physics score will be given preference. And in case there is still a tie then the Chemistry score will be given preference. If the tie persists, candidates with fewer negative markings or wrong answers in the JEE Main paper will be given preference to prepare the merit list. 

Q- In case two candidates have the same marks in Mathematics, Physics, and Chemistry then how will the JEE Main 2024 tie-breaking policy work?

Ans- In such cases, the candidate with the lowest negative answer marked in the JEE Main exam will be given preference. 

Q- Is the JEE Main 2024 Tie-Breaking Policy different for different categories of candidates?

Ans- The JEE Main Tie-Breaking Policy 2024 remains the same for all categories.

Quick Links:

JEE Main 2024 Exam Pattern for Paper 2 (B Arch & B Plan)

The JEE Main 2024 B Arch and B Plan papers are conducted in Computer Based Test mode with the exception of the drawing section which is done as a pen and paper-based test on an A4 paper. Section 1 tests the candidate's mathematical ability whereas section 2 is based on aptitude. JEE Main Paper II exam pattern 2024, marking scheme and tie-breaking policy can be checked below -

Exam Pattern for JEE Main 2024 Paper 2A (B.Arch)

Subjects

Number of Questions

Marks

Mathematics

25 (20+10*)

5 out of 10* questions with numerical answers must be answered

100

Aptitude

50

200

Drawing Test

2

100

Total

82 Questions

400 Marks

JEE Main 2024 Exam Pattern: Paper 2B (B.Plan)

Subjects

Number of Questions

Marks

Mathematics

25 (20+10*)

5 out of 10* questions with numerical answers must be answered

100

Aptitude

50

200

Planning Test

25

100

Total

105 Questions

400 Marks

Q- How many sections are there in the JEE Main Paper 2 for B.Arch?

Ans- There will be three sections in the JEE Main B.Arch paper namely Mathematics, Aptitude, and Drawing.

Q- What is the exam duration of JEE Main 2024 paper 2?

Ans- The candidate will be given a total of 3 hours to solve the JEE Main 2024 BArch and B Plan paper.

Q- What is the mode of JEE Main paper 2 (BArch and BPlan)?

Ans- The JEE Main 2024 B Arch and B Plan examinations are computer-based tests, except for the drawing section, which will be held in offline pen-and-paper mode on A4 paper.

Top Engineering Colleges :

Tie Breaking Policy for JEE Main Paper II

If two or more candidates secure the same marks in the JEE Main Paper II exam, the below rules or tie-breaking policy will be applied to determine the merit of candidates.

Tie Breaker 1:Candidates scoring higher marks in Mathematics in JEE Main Paper II will be given preference in the merit list as per tie-breaker policy 1.

Example:

Let us assume that Candidate A and Candidate B have scored 360 out of 400 marks in JEE Main. However, Candidate A scored 79 marks in Mathematics and Candidate B scored 81 marks. The preference in the order of merit will be given to Candidate B, as he scored higher marks in Mathematics than Candidate A.

Tie Breaker 2: This policy comes into effect when two or more candidates score the same marks in Mathematics. In such cases, candidates with higher marks in the Aptitude Test will be given higher preference in the merit list.

Example:

Let us assume that Candidate A and Candidate B have scored 350 out of 400 marks in JEE Main. However, Candidate A scored 140 marks in Paper II, while Candidate B scored 139 marks. In such cases, Candidate A will be given higher preference in the order of merit than Candidate B.

Tie Breaker 3: This policy comes into effect if two or more candidates score the same marks in the Mathematics and Aptitude Test. In such cases, candidates with higher marks in the Drawing Test will be given preference in the order of merit.

Example:

Let us assume that Candidate A and Candidate B have scored 350 out of 400 in JEE Main Paper-II. On the other hand, these candidates have also scored the same marks in Mathematics and Aptitude Test. However, Candidate A scored 78 marks in the Drawing Test while Candidate B scored 80 marks. In such cases, Candidate B will be the higher preference in the merit list, as he scored higher marks in the Drawing Test than Candidate A.

Tie Breaker 4: This policy comes into effect if two or more candidates score the same marks in Mathematics, Aptitude Test and Drawing Test. In such cases, candidates with fewer negative answers or incorrect answers in the JEE Main Paper-II exam will be given preference in the order of merit.

Example:

Let us assume that Candidate A and Candidate B have scored 250 marks in JEE Main Paper-II. On the other hand, both these candidates score the same marks in Mathematics, Aptitude Test and Drawing Test. However, the number of wrong answers by Candidate A is 16, while the number of wrong answers by Candidate B is 18. In order to determine the merit, Candidate A will be given higher preference in the order of merit, as the number of wrong answers by Candidate A is less than Candidate B.

Tie Breaker 5: This policy comes into effect only if the tie still persists after applying all the above rules. In such cases, candidates older in age will be given higher preference in the merit list. Check the example below for a better understanding.

Example:

Let us assume that Candidate A and Candidate B scored 240 marks in JEE Main Paper-II. On the other hand, these candidates scored the same marks in Mathematics, Aptitude Test and Drawing Test. At the same time, the number of incorrect answers by these candidates is also the same. However, Candidate A is 17 years and 6 months old and Candidate B is 17 years and 8 months old. As per tie-breaker policy 5, Candidate B will be given higher preference in the merit list.

Q- What is the tie-breaking policy for JEE Main Paper II?

Ans- In case two more candidates secure the same marks in JEE Main Paper II NTA will use the tie-breaking policy to break the tie. According to the JEE Main paper II tie-breaking policy, if two candidates get the same score, applicants with higher scores in Mathematics will be given preference while preparing a merit list.

Q- If two or more applicants score the same marks in Mathematics, Aptitude, and Drawing Test then how will the tie be resolved?

Ans- If two or more candidates have the same score in the Mathematics, Aptitude, and Drawing Tests then the candidate with fewer negative or wrong answers in the JEE Main Paper-II exam would be given precedence in the order of merit in such instances.

Q- Who prepares the JEE Main 2024 tie-breaking policy for Paper 2?

Ans- The National Testing Agency (NTA) prepares the JEE Main tie-breaking policy for both Paper 1 and Paper 2.

JEE Main 2024 Marking Scheme (B Tech, BArch & B Plan)

The JEE Main Marking Scheme 2024 for MCQ and NAT sections is the same, the differentiating factor being MCQ has 4 options out of which one is correct whereas the NAT section requires an integer number to be inserted. Since the JEE Main 2024 Drawing section is analytical and logical in nature, candidates will be assessed and marked based on their capabilities. There is no particular negative marking in JEE Main 2024 for the Drawing section.

Particulars

B Tech (Paper 1)

B Arch (Paper 2A)

B Plan (Paper 2B)

Correct Answer 

+4

+4

+4

Incorrect Answer

-1

-1

-1

Unattempted Question

0

0

0

Q- Will there be a negative marking in the JEE Main 2024 exam?

Ans- Yes, there will be negative markings in the JEE Main exam 2024. For every wrong answer, 1 mark of the candidate will be deducted in the exam.

Q- Does the JEE Main 2024 marking scheme varies for paper 1 and 2?

Ans- There is no difference in the JEE Main marking scheme for Papers 1 and 2. For every correct answer candidate will get 4 marks and 1 mark will be deducted for the wrong answer. However, JEE Main paper 2 has a drawing section that is analytical and logical, where a candidate will be given marks as per their skills and abilities. 

Q- If I did not attempt any question in the JEE Main 2024 exam, will my marks be deducted?

Ans- No, in case the candidate did not attempt any question in the JEE Main exam 2024 there will be no marks deduction for unattempted questions as per the marking scheme. 

JEE Main 2024 Negative Marking

In the JEE Main exam, each question typically carries four marks for a correct answer. However, for every incorrect answer, one-fourth (1/4) of the total marks allotted to the question are deducted as negative marks. This means that for every wrong answer, one mark is deducted. 

The scheme applies to both multiple-choice questions (MCQs) and questions with numerical value answers.

  • Multiple-Choice Questions (MCQs): In the case of MCQs, where there are four options provided for a question, if a candidate marks more than one option as the answer, it will be treated as an incorrect response with a JEE Main negative marking. However, if a candidate marks one correct option and leaves the rest unanswered, only the unanswered options will be treated as incorrect with negative markings.

  • Numerical Value Questions: In numerical value questions, where candidates have to enter a numerical answer, there is no JEE Main negative marking for an incorrect response. However, it's important to note that if the answer is not entered in the correct format or if it is rounded off incorrectly, it will be considered an incorrect response and will be awarded zero marks.

It is important to note that questions left unanswered do not carry any penalty. There is no negative marking for unanswered questions, so it is generally advised not to guess randomly if you are unsure about the correct answer.

The purpose of negative marking in JEE Main 2024 is to discourage blind guessing and encourage students to attempt questions only if they have a reasonable level of confidence in their answers. It adds an element of risk in guessing, as incorrect answers can reduce the overall score.

The negative marking is taken into account while determining the total score. Students need to strike a balance between attempting questions they are confident about and leaving questions they are unsure of, to minimize the impact of negative marking on their JEE Mains final score.

Also Check - JEE Main Deleted Syllabus 2024!

JEE Main Syllabus 2024

The National Testing Agency (NTA) has published the JEE Main Syllabus 2024 PDF, as well as the official booklet, on its website. Students can download the JEE Mains syllabus 2024 PDF from jeemain.nta.nic.in. Knowledge about the JEE Main syllabus will help students design a solid study schedule and study the relevant topics for the entrance test. The syllabus for JEE Mains 2024 is based on the 11th and 12th-grade topics of Physics, Math, and Chemistry. As a result, students should begin their test preparation using the NTA JEE syllabus. Students are encouraged to take as many JEE Main Mock Test 2024 Free as possible to have a better understanding of the exam's difficulty level and JEE 2024 syllabus.

This year, NTA has removed many topics from Physics, Mathematics and JEE Main Chemistry Syllabus. The new syllabus is similar to the upgraded NCERT syllabus for Classes 11 & 12. Students can find the JEE Mains Syllabus 2024 PDF Download by NTA at jeemain.nta.nic.in. 

Q- Is the JEE Main syllabus 2024 reduced?

Ans- Yes, NTA has reduced the JEE Main 2024 syllabus. Several topics and chapters have been deleted from the Physics, Chemistry, and JEE Main Maths Syllabus 2024 PDF. 

Q- What subjects are included in the JEE Main Paper 1 and 2 syllabus?

Ans- JEE Main 2024 syllabus for Paper 1 includes Mathematics, Physics, and Chemistry. The syllabus of JEE Main 2024 Paper 2 BArch includes Mathematics, Aptitude, and Drawing Test subjects. The BPlan syllabus consists of Mathematics, Aptitude, and Planning Tests.

Q- What topics are deleted from the JEE Main 2024 Physics syllabus?

Ans- Topics like Transistors, Radioactivity - Alpha, Beta, and Gamma particles/rays and their properties, Potentiometer principles and their applications, Law of radioactive decay etc. have been deleted from the JEE Main Physics Syllabus 2024.

Candidates can check the subject-wise JEE Main 2024 Syllabus here - 

JEE Main Physics Syllabus 2024 PDF

JEE Main Mathematics Syllabus 2024 PDF

JEE Main Chemistry Syllabus 2024 PDF

FAQs about JEE Main Exam Pattern

What is JEE Main Paper 2 Exam?

JEE Main Paper 2 Exam is conducted for admission in B.Arch course.

What is the frequency of JEE Main Paper 2 Exam?

JEE Main Paper 2 exam is conducted four times a year., i.e., February, March, April and May.

What is the mode of JEE Main Paper 2 Exam?

The mode of JEE Main Paper 2 exam is online (computer-based test).

What is the exam pattern for JEE Main Paper 2 Exam?

JEE Main Paper consists of three subjects, i.e., Mathematics, Aptitude Test and Drawing Test. The exam is conducted for 400 marks.

What is the total number of question for JEE Main Paper 2 Exam?

The total number of questions in JEE Main Paper 2 exam are 82 viz., 20+10 questions from Mathematics, 50 from Aptitude and 2 from Drawing Test.

What is the total number of marks in JEE Main Paper 2 Exam?

JEE Main Paper 2 exam is conducted for 400 marks.

Is there any negative marking for JEE Main Paper 2 Exam?

There is negative marking of -1 for MCQ based questions in JEE Main Paper 2 exam. Each wrong attempt by candidate will have a negative mark of -1

How to Use JEE Main College Predictor Tool?

It is simple to use JEE Main college predictor tool. All that you need to do is to enter your JEE Main rank and select the category. Based on the previous years' data, the list of colleges, which are applicable for your rank will be displayed. 

Has there been any major changes in the JEE Main exam pattern 2024?

No, there have been no major changes in the exam pattern. Previously, NTA had introduced an option in the Numerical section. Candidates can now attempt 5 out of 10 questions in the NAT section. There will be a negative marking of -1 for the section.

View More
View All Questions

Related Questions

if i score 150 marks in jee mains 2024, what will be my rank & which college i will get?

-Vishal DindaUpdated on April 13, 2024 02:37 PM
  • 3 Answers
Nidhi Bahl, CollegeDekho Expert

Dear Student,

With 150 marks in JEE Main 2024, your rank will be between 18,000 and 20,000. This implies your percentile might fall around 98-99. With this rank, you can get admission to top colleges like NIT Warangal, Surathkal, Trichy, Raipur, Rourkela, Jamshedpur, etc., in branches like Computer Science Engineering (CSE), Electrical and Electronics Engineering (EEE), Information Technology (IT), etc. Apart from this, you can also have good chances for admission into top GECs in your state for various branches depending on the state and college cutoffs.

READ MORE...

Which College i will get for 90 Percentile in JEE Mains 2024?

-Himanshu SenUpdated on February 18, 2024 12:02 PM
  • 3 Answers
Nidhi Bahl, CollegeDekho Expert

Dear Student,

90 percentile in JEE Main is a very good percentile which can get you some of the prominent colleges like IIT Guwahati, IIT Indore, IIT Mandi, IIT Patna, or IIT Ropar) for various branches, depending on your category and branch preference. Top IITs like Bombay, Delhi, Madras, etc., might be more challenging but not impossible. You'll also have excellent opportunities for admission into top NITs like Warangal, Surathkal, Trichy, Raipur, Rourkela, Jamshedpur, etc., for various branches like CSE, EEE, IT, Mechanical, Civil, Chemical, etc. with this percentile.

READ MORE...

I got 43256 rank in JEE Main under EWS category. Am I eligible for B.Tech CSE at Graphic Era, Dehradun?

-VivekUpdated on February 08, 2024 11:45 PM
  • 6 Answers
Diksha Sharma, Student / Alumni

Dear Student,

Yes, you are eligible for admission to B.Tech CSE at Graphic Era, Dehradun with your JEE Main score. 

To learn about all complete details for B.Tech CSE course including the eligibility, fees, admission, fees, etc., read B.Tech CSE or B.Tech Software Engineering.

Also, do not miss out on the Government Job Scope after B.Sc Computer Science and B.Tech Computer Science Engineering.

You can also fill the Common Application Form on our website for admission-related assistance. You can also reach us through our IVRS Number - 1800-572-9877.

READ MORE...

Still have questions about JEE Main Exam Pattern ? Ask us.

  • Typical response between 24-48 hours

  • Get personalized response

  • Free of Cost

  • Access to community

Tell us your JEE Main score & access the list of colleges you may qualify for!

Predict My College
Top
Planning to take admission in 2024? Connect with our college expert NOW!