JEE Main Marks vs Percentile Analysis 2 April 2026 by Top Experts: Session 2 Shift 1 & 2 Difficulty Level

Angana Nath

Updated On: April 03, 2026 09:13 AM

JEE Main Marks vs Percentile Analysis for April 2, 2026 Shift 1 is available. Percentile, crucial for NITs/IIITs, depends on shift difficulty, candidate count, and top scores. Experts used previous trends and a formula for this analysis. The table shows expected marks vs percentile for a moderate Shift 1 paper.
JEE Main Marks vs Percentile Analysis 2 April 2026 by Top ExpertsJEE Main Marks vs Percentile Analysis 2 April 2026 by Top Experts

JEE Main Marks vs Percentile Analysis 2 April 2026: Candidates are often curious to know the JEE Main marks vs percentile analysis, since raw scores are not considered for obtaining ranks. The relationship between the marks vs percentile is solely dependent on some external factors, such as the difficulty level of the specific shift, the total number of candidates who appeared, and the performance of the top scorer in the shift.

Also read | JEE Main 2026 April 4 Exam LIVE

JEE Main Marks vs Percentile Analysis 2 April 2026 for Shift 1 and 2

Today is the first day 1 of Session 1 JEE Main 2026 exam. Candidates can check the JEE Main 2 April shift 1 and 2 marks vs percentile analysis here, prepared by the CollegeDekho top subject-matter experts. Note that the analysis is made for the moderate-level paper.

Percentile

Marks (Moderate Shift)

Expected Rank

99.99

240

140

99

176

14000

95

120.5

70000

90

90

140000

85

72

210000

80

56.1

280000

75

45.5

350000

70

41.4

420000

65

37.8

490000

60

34.1

560000

55

31

630000

50

28.4

700000


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To analyse the JEE Main marks vs percentile, previous years’ trends have been considered. So that candidates aiming to secure a seat at any of the top-ranked NITs or IIITs can refer to the JEE Main marks vs percentile analysis beforehand (before releasing the result).

To calculate the percentile using the JEE Main raw scores, the following formula has been used:

Percentile = [(Number of candidates with raw score ≤ your score)/ Total number of candidates in the shift] X 100

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