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Today is the last day to raise objection on CSIRE UGC NET 2022 answer key. The National Testing Agency (NTA) earlier released the CSIR UGC NET 2022 provisional Answer Key on 1st October 2022 on the official website of CSIR NET @csirnet.nta.nic.in. All the candidates are allowed to challenge the questions, if any against the initial answer key released for CSIR UGC NET 2022 till 3rd October 2022 at 11:50 PM as it is the last day to raise objections.
The CSIR NET 2022 examination was conducted from 16th to 18th September 2022 in a total of 166 examination cities across the Country. The answer key challenge window is kept active from 1st to 3rd October 2022. The applicants should also take care of the fact that the last day to pay the online fee for UGC NET answer key challenge 2022 is also 3rd October 2022. The candidates can raise objections to the answer key by paying an online fee of INR 200 per question before midnight today.
CSIR UGC NET 2022 Answer Key Important Dates
CSIR UGC NET 2022 Exam Date
16th October 2022 - 18th October 2022
CSIR UGC NET 2022 Answer Key Release Date
1st October 2022
UGC NET Answer Key Challenge Window
1st October 2022 to 3rd October 2022 (till 11:50 PM)
CSIR NET 2022 Final Answer Key 2022
How to Challenge CSIR UGC NET Answer Key 2022?
Click on the CSIR NET 2022 Answer Key Challenge Link provided above or visit @csirnet.nta.nic.in
Click on the link named “Display Question Paper and Answer Key Challenge” on the CSIR NET homepage
You can check the answer by two methods, either by application number and password or by providing the Application number and date of birth
Check the provisional answer key for CSIR UGC NET 2022 exam
Click on the Option ‘Raise Objection on the Answer Key’ if you find any discrepancy
Choose the question number(s) for which you want to raise an objection and select the claimed correct option for answer
Upload the reference document to support your objection on answer key
Pay the online Answer key challenge fee (INR 200 per question challenged)
Submit your objection and download the same for reference
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