COMEDK UGET 2026 Electrochemistry Practice Questions with Solutions

COMEDK UGET 2026 Electrochemistry Practice Questions with Solutions are an essential part of your Chemistry preparation if you are targeting a strong score in the entrance exam conducted by Consortium of Medical, Engineering and Dental Colleges of Karnataka. Electrochemistry is a concept-driven yet scoring chapter that consistently appears in COMEDK UGET with direct, application-based numerical questions. When you practise well-structured questions along with step-by-step solutions, you not only strengthen your conceptual clarity but also improve speed and accuracy—both of which are critical in a time-bound computer-based test. This chapter usually carries moderate weightage, and with focused preparation, you can confidently convert these questions into sure-shot marks.

From Electrochemistry, you should concentrate mainly on electrochemical cells, galvanic and electrolytic cells, standard electrode potential, Nernst equation, EMF of a cell, electrolysis, Faraday’s laws, conductance, specific and molar conductivity, Kohlrausch’s law, and corrosion. The nature of questions asked in COMEDK UGET is largely numerical-based, requiring direct formula application with slight conceptual twists. You will often encounter questions where values are substituted into the Nernst equation, calculation of cell potential under non-standard conditions, determination of conductance or molar conductivity at infinite dilution, and straightforward problems based on Faraday’s laws of electrolysis. The paper generally avoids lengthy calculations, instead testing how well you understand the core concepts and relationships between variables.

If you analyse previous year COMEDK UGET papers, you will notice that Nernst equation, EMF calculation, electrochemical series, Faraday’s laws, and conductivity-related numericals are repeatedly asked areas from Electrochemistry. To prepare effectively, you should first build a strong conceptual base by revising formulas and understanding their derivations at a basic level. Next, practise a wide variety of COMEDK-level objective questions, focusing on accuracy rather than complexity. While solving practice questions, time yourself and review solutions carefully to identify common mistakes. Regular revision of formulas, practising previous year questions, and solving mock tests will ensure that Electrochemistry becomes one of your most reliable scoring chapters for COMEDK UGET 2026.

Also Check -COMEDK Chapter Wise PYQs for Chemistry

COMEDK UGET 2026 Electrochemistry Important Topics

With several sub-topics included in COMEDK UGET Electrochemistry, such as Redox reactions, Lead accumulator, Nerst equation and its application to chemical cells, this chapter plays an important role in the exam preparation. If you wish to sit for theCOMEDK UGET 2026 exam, then you must make sure to be well-acquainted with all the topics of the Electrochemistry chapter. You can find more details related to COMEDK UGET Electrochemistry sub-topics for exam preparation below:-

Also Check -Do or Die Chapters for COMEDK UGET 2026 Chemistry

COMEDK UGET 2026 Electrochemistry Expected Weightage

Electrochemistry chpater holds approximately 5% of the total weightage inCOMEDK UGET 2026 Chemistry syllabus. While doing your preparation/ revision, you are advised to have a good knowledge of the expected weightage as well as the number of questions that will be asked from the said chapter. The table below entails the crux related to the information of COMEDK UGET 2026 Electrochemistry expected weightage:-

Important Portions from Electrochemistry & How to Study?

Check the important portions from the chapter.

Previous Year COMEDK Question Mapping from Electrochemistry

Check the nature of questions asked in previous year from this chapter.

Year Wise No of Electrochemistry Questions Asked in COMEDK

Check the no of questions asked in the last 5 to 6 years.

COMEDK UGET 2026 Electrochemistry Practice Questions with Solutions

Regularly practicing COMEDK Electrochemistry sample questions can significantly enhance your exam preparation. Working through COMEDK Electrochemistry practice questions with solutions allows you to familiarize yourself with potential exam questions, verify correct answers, and understand step-by-step solutions. Below are some essential COMEDK UGET 2026 Electrochemistry practice questions, carefully selected from past exam papers:-

Q1. What is the quantity of charge, in Faraday units, required for the reduction of 3.5 moles of Cr₂O^2-₇in acid medium?

a) 6.0

b) 10.5

c) 21.0

d) 3.0

Correct answer -c) 21.0

Solution:To determine the quantity of charge, in Faraday units, required for the reduction of 3.5 moles of Cr₂O^2-₇in acid medium, we need to look at the half reaction for the reduction of Cr₂O^2-₇to Cr³⁺:

Cr₂O^2-₇+ 14H⁺+ 6e- ⇾ 2Cr³+ 7H₂O

The balanced equation shows that 6 moles of electrons (e-⁾are needed to reduce 1 mole of Cr₂O^2-₇. Therefore, for 3.5 moles of Cr₂O^2-₇

The total charge required in moles of electrons is calculated as:

Total charge = 3.5 moles\ of CR2O^2-₇x 6 moles of e-/mole\ofCr₂O^2-₇

So:

Total charge = 3.5 x 6 = 21 Faradays

Thus, the quantity of charge required for the reduction of 3.5 moles of Cr₂O^2-₇in acid medium is 21.0 Faradays.

The correct answer is Option C: 21.0

Q2. A dry cell consists of a moist paste of NH₄Cl and ZnCl₂contained in a Zn casing which encloses a Carbon rod surrounded by black Mno2 paste. What is the role of ZnCl₂in it?

a) It prevents pressure being developed in the cell due to NH3 gas formation.

b) It serves as cathode thus permitting Carbon rod to act as anode.

c) It acts as the anode while Carbon rod acts as the cathode.

d) It keeps the contents dry and prevents leakage of electrolyte.

Correct answer -a) It prevents pressure being developed in the cell due to gas formation

Solution:In a dry cell, the following reactions occur:

At the anode (Zinc casing):

Zn(s)→Zn²+(aq)+2e^-

At the cathode (Carbon rod):

2MnO₂(S) + 2NH⁺₄(aq)+2e^-→Mn2O₃(s) + 2NH3(aq) + H₂O(l)

The ammonia (NH3) produced at the cathode is a gas. If it's not controlled, it can build up pressure inside the cell, potentially causing it to leak or even explode.

The role of ZnCl₂is to react with the ammonia to form a complex ion:

Zn²⁺(aq) + 4NH₃(aq)⇌[Zn(NH₃)₄]²⁺(aq)

This reaction effectively removes the ammonia gas from the system, preventing the buildup of pressure and ensuring the stability of the cell.

Let's look at why the other options are incorrect:

Option B: The cathode is the carbon rod where reduction occurs, and the anode is the zinc casing where oxidation takes place. The Zinc doesn't directly affect this role.

Option C: Zinc acts as the anode, not the cathode. The carbon rod acts as the cathode.

Option D: ZnCl₂doesn't prevent the leakage of the electrolyte. The cell's design and the paste's consistency are more important for preventing leaks.

Q3. Identify the incorrect statement among the following.

a) Electrolytic conductance increases with increase in temperature

b) Conductivity does not depend on the viscosity of the solution

c) Conductivity depends on the size of the ions

d) Conductivity depends on the solvation of the ions

Correct answer:b) Conductivity does not depend on the viscosity of the solution

Solution:Let's analyze each option:

Option A: "Electrolytic conductance increases with increase in temperature."

As temperature increases, ions move faster due to decreased viscosity and increased kinetic energy. This leads to higher conductance. Therefore, Option A is correct.

Option B: "Conductivity does not depend on the viscosity of the solution."

Viscosity affects the mobility of ions. According to models like the Stokes-Einstein relation, higher viscosity means lower ion mobility, which decreases conductivity. Hence, conductivity does indeed depend on viscosity, making Option B incorrect.

Option C: "Conductivity depends on the size of the ions."

Smaller ions typically move faster than larger one, leading to better conductivity. Thus, the size of the ions has an effect on conductivity, making Option C correct.

Option D: "Conductivity depends on the solvation of the ions."

Solvation affects the effective size and mobility of the ions. Strong solvation increases the effective radius and may reduce mobility, thereby affecting conductivity. So, Option D is also correct.

Based on the analysis, the incorrect statement is:

Option B

Q4. When Lead Storage battery is in the process of getting charged which one of the following reactions takes place?

a) PbO_2(s)is reduced.

b) PbSO_4(s)gets converted to Pb(s) and PbO2_(s)

c) SO₃gas gets liberated and PbO2(s) is formed

d) Pb_(s)gets confused

Correct answer:b) PbSO_4(s)gets converted to Pb(s) and PbO2_(s)

Solution:

The lead-acid battery charging process involves reversing the chemical reactions that occur during discharging. In a lead-acid battery, there are two electrodes: a lead dioxide (PbO2) cathode and a lead (Pb) anode, both immersed in an electrolyte of sulfuric acid (H₂SO₄).

During the discharge process, at the anode (negative electrode), lead (Pb) is oxidized to lead sulfate (PbSO4):

Pb+SO^2-₄→PbSO₄+2e^-

At the cathode (positive electrode), lead dioxide (PbO2) is reduced to lead sulfate (PbSO4) as well using the electrons that flow through the external circuit:

PbO₂+ 4H⁺+ SO^2-₄+ 2e^-→PbSO₄+ 2H₂O

When the battery is being charged, these reactions are reversed. At the anode:

PbSO₄+ 2e^-→Pb + SO^2-₄

This is where lead sulfate is converted back to metallic lead. And at the cathode:

PbSO₄+ 2H₂O → PbO₂+ 4H⁺+ SO^2-₄+ 2e^-

Here, lead sulfate is converted back to lead dioxide.

In this context, Option B is the correct answer. During the charging process, PbSO4 indeed gets converted to Pb and PBO2 and according to the reactions described. To be specific, these reactions take place at the two different electrodes of the battery (lead sulfate at both electrodes being converted into lead and lead dioxide, respectively).

Q5. For a cell reaction, A(s) + B²⁺(aq) → A²⁺(aq) + B(s); the standard emf of the cell is 0.295V at 25°C. The equilibrium constant at 25°C will be:

a) 1 x 10¹⁰

b) 10

c) 2.95 x 10^-2

d) 2.95 x 10^-10

Correct answer:a) 1 x 10¹⁰

Solution:

For this given reaction, n = 2. At 25°C,

K = antilog [nE°/0.059] = antilog [2x(-0.295/0.059]

K = 1x10¹⁰

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