Organic Chemistry Weightage in JEE Mains 2025 is expected to be 28% to 32% of the Chemistry section. However, the overall weightage of Organic Chemistry Weightage in JEE Mains (full paper) is 3.3% which is equivalent to 1 question asked in the exam. As per previous years trends, the weightage of General Organic Chemistry (GOC) is expected to be 6 to 8%, Hydrocarbons is 5 to 6%, Alcohols, Phenols, and Ethers are 4 to 5%, Aldehydes, Ketones, and Carboxylic Acids is 5-6%. The important chapters holding a high weight in Organic Chemistry are General Organic Chemistry (GOC), Aldehydes, Ketones, Carboxylic Acids, Hydrocarbons, Alcohols, Phenols, Ethers, etc.

To prepare for the Organic Chemistry Topic in JEE Main 2025 Exam , candidates need to focus on reaction mechanisms, especially nucleophilic substitution and electrophilic addition, memorize named reactions and functional group interconversions, and solve application-based problems to build conceptual clarity. Check the Organic Chemistry Weightage in JEE Mains 2025 here.

Expected Organic Chemistry Weightage in JEE Mains 2025

The expected JEE Mains 2025 Organic Chemistry Weightage has been provided below.

Organic Chemistry Weightage in JEE Mains (Previous Years Analysis)

As per previous years analysis, Organic Chemistry is one of the most important chapters of JEE Mains Chemistry Paper. Candidates preparing for JEE Mains 2025 are advised to check the detailed analysis of the previous five years Organic Chemistry Weightage along with the topics with high weightage.

Preparation Tips for Organic Chemistry in JEE Mains Chemistry 2025

Check the JEE Mains Chemistry 2025 Preparation Tips for Organic Chemistry from the pointers below.

• Focus on reaction mechanisms, particularly nucleophilic substitution, electrophilic addition, and elimination reactions.
• General Organic Chemistry (GOC) is one of the most important and highest weight topics.
• Aldehydes, Ketones, and Carboxylic Acids are asked with conceptual and numerical questions.
• Moderate to difficult questions are asked about alcohol, Phenols, and Ethers.
• Easy-scoring questions, that require memorization are Biomolecules and Polymers.
• Review named reactions and their applications in problem-solving.
• Understand the interrelation of topics (e.g., GOC's impact on understanding reactivity in Aldehydes).
• Prioritize topics like GOC, Hydrocarbons, and functional group chemistry for higher returns.

Also Read: Best JEE Main Coaching Institutes in India

JEE Main 2025 Exam Pattern

Check the JEE Main exam pattern 2025 below:

• The JEE Main 2025 exam will be conducted in 3 sections: Physics, Chemistry and Mathematics.
• Each subject from JEE Mains Paper will be divided into two sections: Section A and Section B.
• JEE Main 2025 exam Section A will comprise 20 MCQs (Multiple Choice Questions).
• Section B of the JEE Main 2025 exam Paper will comprise 5 NVQs (Numerical Value Questions).
• Each question from JEE Main will hold a total of +4 marks for correct answers and -1 mark for incorrect answers.
• The JEE Main exam 2025 will be conducted for a total of 300 marks and 3 hours (180 minutes).

JEE Mains 2025 Organic Chemistry Sample Questions

Practice the JEE Mains Sample Questions for Organic Chemistry below -

1. The most basic compound among the following is:-

(1) Acetanilide

(2) Benzylamine

(3) p-Nitro aniline

(4) Aniline

Solution:

Basicity is inversely proportional to the resonance of lone pair electrons. Benzylamine is more basic. The electron pairs are not involved in resonance in benzylamine. In other amines, there is delocalization of a lone pair of electrons on the N atom on the ring. In acetanilide, the delocalization of a lone pair of electrons on the N atom is due to the adjacent CO group.

Hence option (2) is the answer.

1. Considering the basic strength of amines in aqueous solution, which one has

the smallest pKb value?

(1) (CH3)3N

(2) C6H5NH2

(3) (CH3)2NH

(4) CH3NH2

Solution:

Because of resonance, arylamines are less basic than alkyl amines. In arylamines, the lone pair of electrons on N is partly shared with the ring and is less available for sharing with a proton. In alkylamines, the electron-releasing alkyl group increases the electron density of the nitrogen atom. Hence increases the protonation ability of amines. So, the more the number of alkyl groups, the higher be basicity of amine. Because of the steric effect, a slight discrepancy occurs in the case of trimethyl amine. So (CH3)2NH has the smallest pKb value.

Hence option (3) is the answer.

1. Ortho-nitrophenol is less soluble in water than p– and m– Nitrophenols because:

(1) The melting point of o–Nitrophenol is lower than those of m– and p– isomers

(2) o–Nitrophenol is more volatile in steam than those of m– and p– isomers

(3) o–Nitrophenol shows Intramolecular H–bonding

(4) o–Nitrophenol shows Intermolecular H–bonding

Solution:

Intramolecular H-bonding is present in o-nitrophenol. So solubility in water is decreased.

Hence option (3) is the answer.

1. Which one of the following compounds will not be soluble in sodium bicarbonate?

(1) Benzene sulphonic acid

(2) Benzoic acid

(3) o-Nitrophenol

(4) 2, 4, 6 – Trinitrophenol

Solution:

Benzene sulphonic acid and Benzoic acid are stronger acids and they react with sodium bicarbonate. o-Nitrophenol is a very weak acid and it does not react with sodium bicarbonate. o-Nitrophenol will not be soluble in sodium bicarbonate. 2, 3, 6 – Trinitrophenol is higher in acidity and it reacts with sodium bicarbonate.

Hence option (3) is the answer.

1. The compound formed in the positive test for nitrogen with the Lassaigne solution of an organic compound is

(1) Fe4[Fe(CN)6]3

(2) Na4[Fe(CN)5NOS]

(3) Fe(CN)3

(4) Na3[Fe(CN)6]

Solution:

The compound formed in the positive test for nitrogen with the Lassaigne solution of an organic compound is the Prussian blue-coloured complex compound ferric ferrocyanide.

Hence option (1) is the answer.

1. Which one of the following conformations of cyclohexane is chiral?

(1) Twist boat

(2) Rigid

(3) Chair

(4) Boat

Solution:

Twist boat is chiral because it does not have a plane of symmetry.

Hence option (1) is the answer.

1. Among the following oxoacids, the correct decreasing order of acid strength is :

(1) HClO4 > HClO3 > HClO2 > HOCl

(2) HClO2 > HClO4 > HClO3 > HOCl

(3) HOCl > HClO2 > HClO3 > HClO4

(4) HClO4 > HOCl > HClO2 > HClO3

Solution:

Acidic strength is directly proportional to the oxidation number. Increasing acid strength is because of an increase in the oxidation state of the central atom.

Hence option (1) is the answer.

1. Among the following the molecule with the lowest dipole moment is:-

(1) CHCl3

(2) CH2Cl2

(3) CCl4

(4) CH3Cl

Solution:

Dipole moment of CCl4 is 0.

The order of dipole moment is CCl4 < CH3Cl < CH2Cl2 < CHCl3.

Hence option (3) is the answer.

1. The order of basicity of amines in the gaseous state is :

(1) 30 > 20 > NH3 > 10

(2) 10 > 20 > 30 > NH3

(3) NH3> 10 > 20 > 30

(4) 30 > 20 > 10 > NH3

Solution:

The basicity is proportional to the +I effect. The presence of an electron-donating group increases the basicity of amines. The presence of a withdrawing group decreases the basicity of amines.

Hence option (4) is the answer.

1. The general formula CnH2n02 could be for open-chain

(1) carboxylic acids

(2) diols

(3) dialdehydes

(4) diketones

Solution:

The general formula CnH2n02 could be for open-chain carboxylic acid or ester.

Hence option (1) is the answer.

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