
States of Matter JEE Main Questions 2025 - As JEE Main 2025 is approaching, candidates should fasten their preparation and be ready with the topics of JEE Main 2025 Chemistry by now. JEE Main Chemistry 2025 is one of the easiest yet tactical subjects that helps fetch good score in JEE Mains with a proper preparation strategy. Approximately 2 questions are asked from States of Matter every year in the JEE Mains entrance exam which is equivalent to 6.6% weightage. Therefore, candidates are advised to prepare well for the chapter by practising the JEE Main 2025 States of Matter Questions. Some of the important topics that hold the highest weightage from States of Matter JEE Main are Ideal Gas Equation and Real Gases, Kinetic Theory of Gases, Boyle’s, Charles’s, Avogadro’s Laws, etc. In this article, we have discussed the States of Matter JEE Main Questions 2025 where candidates can practice the Important Questions that are extracted from Previous years questions.
Quick Links:
JEE Main Syllabus 2025 | Best Books for JEE Main 2025 |
---|---|
JEE Main Previous Year Question Papers | JEE Main Sample Paper |
JEE Main 2025 States of Matter Important Questions
Students can check questions for JEE Main 2025 States of Matter important questions along with their solutions from here1. If Z is the compressibility factor, van der Waals’ equation at low pressure can be written as :
(1) Z=1-Pb/RT
(2) Z=1+Pb/RT
(3) Z = 1+RT/Pb
(4) Z = 1-a/VmRT
Solution:
(P+a/Vm2 )(Vm-b) = RT [Van der waals equation of state]
Vm-b ≈ Vm
So the equation becomes (P+a/Vm2 )Vm= RT
⇒PVm+a/Vm = RT
Divide all terms by RT
PVm/RT+a/VmRT = RT/RT
PVm/RT = 1- a/VmRT
Z = 1- a/VmRT [Z = PVm/RT]
Hence option (4) is the answer.
Also Read:
JEE Main 2025 Preparation and Study Time Table for 60 Days (2 Months)
2. Which intermolecular force is most responsible for allowing xenon gas to liquefy?
(1) Instantaneous dipole induced dipole
(2) Ion dipole
(3) Ionic
(4) Dipole-dipole
Solution:
For the liquefaction of xenon, instantaneous dipole-induced dipole forces are responsible.
Hence option (1) is the answer.
3. The temperature at which oxygen molecules have the same root mean square speed as helium atoms have at 300 K is : (Atomic masses: He = 4 u, O = 16 u)
(1) 1200 K
(2) 600 K
(3) 300 K
(4) 2400 K
Solution:
Given Atomic masses : He = 4 u, O = 16 u
(Vrms) O2 = (Vrms) He
√(3RT1/M1) = √(3RT2/M2)
T1 /M1 = T2/M2
T1/32 = 300/4
T1 = 300×32/4
= 2400 K
Hence option (4) is the answer.
4. The compressibility factor for a real gas at high pressure is :
(1) 1-Pb/RT
(2) 1+ RT/Pb
(3) 1
(4) 1+Pb/RT
Solution:
(P+a/V2)(V-b) = RT [Real gas equation]
a/V2 can be neglected at high pressure.
PV-Pb = RT
PV/RT = (RT/RT) + (Pb/RT)
PV/RT = 1 + (Pb/RT) …(1)
Z = PV/RT …(2)
Equating (1) and (2)
Z = 1 + (Pb/RT)
Hence option (4) is the answer.
5. The relationship among most probable velocity, average velocity and root mean square velocity is respectively :
(1) √2 : √(8/π) : √3
(2) √2 :√3 : √(8/π )
(3) √3 : √(8/π): √2
(4) √(8/π) : √3: √2
Solution:
Vmpv = √(2RT/M)
Vav = √(8RT/πM)
Vrms = √(3RT/M)
Vmpv: Vav: Vrms. = √(2RT/M) : √(8RT/πM) : √(3RT/M)
= .√2 : √(8/π) : √3
Hence option (1) is the answer.
6. The value of gas constant R is
(1) 0.082 L atm
(2) 0.987 cal mol-1 K-1
(3) 8.3 J mol-1 K-1
(4) 83 erg mol-1K-1
Solution:
R = 8.3 J mol-1 K-1
Hence option (3) is the answer.
7. By how much does the temperature of a gas increase when the root mean The square velocity of the gas molecules in a container of fixed volume is increased from 5×104 cm/s to 10×104 cm/s.
(1) Four
(2) three
(3) Two
(4) Six
Solution:
Vrms ∝ √T
V1/V2 = √(T1/T2) = 5×104/10×104
squaring, we get
T1/T2 = 25/100 = ¼
T2 = 4T1
Hence option (1) is the answer.
8. The kinetic theory of gases proves
(1) Only Boyle’s law
(2) Only Charle’s law
(3) Only Avogadro’s law
(4) all of these
Solution:
One of the postulates of the kinetic theory of gases is average kinetic energy proportional to T.
This theory proves all the above-given laws.
Hence option (4) is the answer.
9. Which one of the following is the wrong assumption of the kinetic theory of gases?
(1) All the molecules move in a straight line between collision and with the same velocity.
(2) Molecules are separated by great distances compared to their sizes.
(3) Pressure is the result of elastic collision of molecules with the container’s wall.
(4) Momentum and energy always remain conserved.
Solution:
The molecules are always in random motion and obey Newton’s law of motion. They have velocities in all directions ranging from zero to infinity.
Hence option (1) is the answer.
10. ‘a’ and ‘b’ are Vander Waal’s constants for gases. Chlorine is more easily liquified than ethane because:
(1) a for Cl2 < a for C2H6 but b for Cl2 > b for C2H6
(2) a for Cl2 > a for C2H6 but b for Cl2 < b for C2H6
(3) a and b for Cl2 > a and b for C2H6
(4) a and b for Cl2 < a and b for C2H6
Solution:
The greater the ‘a’ value, the more easily the gas is liquified, the lower the ‘b’ value, the more easily the gas is liquified.
Hence option (2) is the answer.
States of Matter JEE Main 2025 Important Topics
Check the important sub-topics from JEE Main States of Matter from the table below.States of Matter Topics |
States of Matter Sub-Topics
|
---|---|
Ideal Gas Equation and Real Gases |
|
Kinetic Theory of Gases |
|
Boyle’s, Charles’s, and Avogadro’s Laws |
|
Dalton's Law of Partial Pressures |
|
Graham's Law of Diffusion |
|
Critical Phenomena |
|
States of Matter JEE Main Questions 2025 PDF (Previous Years Questions)
Practice the important previous years' States of Matter JEE Main Questions from the following PDF provided below.
Related Articles:
We hope this article has been helpful for the candidates to be aware of the State of Matter JEE Main Important Practice Questions with PYQs. You can just fill out the Common Application Form on our website, it is a single application form for securing admission into various universities. For more articles and updates on JEE Main 2025, stay tuned with CollegeDekho.
Are you feeling lost and unsure about what career path to take after completing 12th standard?
Say goodbye to confusion and hello to a bright future!
FAQs
The JEE Main exam incorporates various question types, comprising multiple-choice questions (MCQs), numerical value-based questions, as well as drawing-based questions. With MCQs, candidates must select the correct answer from the given options.
No. The JEE Mains exam alone is not enough for securing admission into an IIT. JEE Advanced is the crucial examination required for IIT admissions, and candidates are required to qualify in the JEE Main exam to be eligible for the JEE Advanced exam.
Yes, 90 is considered to be a good percentile in the JEE Main 2025 entrance exam. Candidates can secure admission into NITs, IITs or IISc Bangalore if they score a rank between 1,00,000 and 1,50,000 with a 90 percentile in the JEE Main exam.
Mathematics is often considered to be the most challenging subject in the JEE Main exam, but its difficulty level varies from person to person. Some students may find other subjects more challenging based upon their strengths and weaknesses.
NCERT books are very important to prepare for the JEE Main 2025 exam. The JEE Main exam follows the CBSE syllabus for 11th and 12th classes, so NCERT books are considered to be the most reliable and necessary study materials. NCERT books explain basic fundamental concepts in a simple and clear way.
To score a 99+ percentile in the JEE Main 2025 exam, candidates require more than just knowing the JEE Main syllabus, as it required consistent practice, strategic revision, time management, and the ability to solve complex problems under pressure. However, with the appropriate resources, one can achieve these requirements.
All sections namely Mathematics, Physics, and Chemistry are mandatory in the JEE Main exam, with questions covering the entire JEE Main syllabus. To be eligible for admission, candidates must achieve the minimum qualifying marks in each subject and the overall aggregate.
Candidates can study from the NCERT textbooks of class 11 and 12 Physics, Chemistry and Mathematics to cover the JEE Mains syllabus. No changes have been made to the JEE Main Syllabus 2025. NTA removed several topics of Physics, Chemistry and Mathematics last year from the JEE Main syllabus.
Candidates must keep in mind that there is no requirement of 75% marks in class 12 for appearing in the JEE Mains exam. The JEE Main eligibility criteria of minimum 75% marks in class 12 is required at the time of securing admission across NITs, IIITs and GFTIs. Candidates can apply and appear in the JEE Mains 2025 exam irrespective of their class 12 marks.
Previous year question papers are an important source for the JEE Main preparations. However, relying solely upon PYQs is not enough to fully prepare for the JEE Mains exam. Candidates must also focus on covering the entire syllabus, developing strong conceptual understanding, practising time management, and attempting mock tests.
The JEE Main 2025 marking scheme is similar to the other topics of the Chemistry Syllabus where candidates will be awarded 4 marks for every correct answer and 1 mark will be deducted for every incorrect answer.
The separation of gases with varying densities can be achieved through Graham's law. It is also useful in finding the molar mass of unknown gases by analyzing the diffusion rate of the unknown gas in relation to a known gas. Isotopes of an element can be separated by applying Graham's law. A typical example of this is the enrichment of uranium from its isotopic form.
The human lungs are elastic, air-filled structures that play a crucial role in the process of respiration. Air enters the lungs when they expand and is expelled when they contract. During the winter months, the air temperature drops. As a result, the air temperature inside the body also lowers. According to Charles's law, volume is directly related to temperature. Therefore, as the temperature decreases, the volume of air reduces. This contraction of the lungs makes physical activities, such as jogging, more challenging on cold winter days.
Many of us have experienced a syringe during a visit to the doctor. It is a medical instrument designed for injecting or extracting liquid. It comprises a hollow tube known as a barrel and a movable plunger attached to it. The functioning principle of a syringe resembles that of a reciprocating pump. When the plunger is pressed, the fluid is injected, and when it is pulled, the fluid is withdrawn; pushing the plunger decreases the fluid's volume in the barrel. This decrease in volume leads to a temporary rise in the fluid's pressure, allowing it to be injected into the patient's body. Likewise, pulling the plunger increases the fluid's volume, resulting in a temporary pressure drop, which causes external fluid to be drawn in.
To prepare for states of matter in jee mains, you have to follow a simple rule as the entire concept surrounds our daily activities. You are required to study the previous year's questions, practice problems to build confidence and learn to apply theoretical knowledge to real-world strategies.
The important topics of state of matter are gas laws, kinetic theory, real gases, phase transitions, and properties of liquids and solids.
The states of matter is a key topic in the JEE Main Chemistry syllabus, encompassing solids, liquids, and gases. Solids possess a definite volume and shape due to strong forces of attraction that hold their particles together. Liquids, while having a definite volume, do not have a fixed shape, as their particles are held by weaker forces of attraction. In contrast, gases lack both a definite volume and shape, with particles that experience almost no forces of attraction.
Approximately 2 questions are asked from States of Matter every year in the JEE Mains entrance exam which is equivalent to 6.6% weightage.
Approximately 2 questions are asked from States of Matter every year in the JEE Mains entrance exam which is equivalent to 6.6% weightage.
JEE Main Previous Year Question Paper
Was this article helpful?




Similar Articles
GATE 2025 EY Expected Qualifying Cutoff Marks
GATE 2025 MN Question Paper Analysis: Unofficial Answer Key with Solutions
GATE 2025 PI Question Paper Analysis: Unofficial Answer Key with Solutions
GATE 2025 BM Expected Qualifying Cutoff Marks
GATE 2025 ES Question Paper Analysis (Out): Unofficial Answer Key with Solutions
GATE Rank vs Marks vs Score Analysis 2025