Updated By Soham Mitra on 25 May, 2022 13:50
26 days Remaining for the exam
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The National Testing Agency (NTA) has released the exam pattern of JEE Main 2022 on its official website  jeemain.nta.nic.in. As per the paper pattern, JEE Main exam 2022 will be conducted in two sessions (June and July) having two papers  Paper 1 (B.E/B.Tech) and Paper 2 (B.Arch or B.Plan). JEE Main 2022 exam pattern is similar to the exam patterns of previous years , except that the optional questions will have negative marking this year. The number of questions in the entrance exam increased from 75 to 90 in 2021. As per the paper pattern, each subject will have 30 questions now. The candidates must note that Section B consists of numerical questions, and he/ she will have the option to answer any five questions out of 10. There is no choice in Section A. The detailed exam pattern can be checked below.
After going through the latest pattern for this year's JEE Main examination, the candidates should also take a good look at the detailed eligibility criteria of JEE Main 2022. Once satisfied, the candidates must proceed with the application process.
Also Read  JEE Main 2022 Preparation and Study Time Table for 60 Days (2 Months)
Each topic will have two parts in the JEE Main 2022 examination paper. Section A will have 20 required multiplechoice questions, but Section B will include 10 numerical questions, of which students must answer just five. Both Section A and Section B will receive negative marking. The students should insert the right integer value of the answer for each question in Section B using the mouse and the onscreen virtual numeric keypad in the location indicated to enter the answer. Section B requires the answer to be rounded to the nearest Integer.
Here are some of the major changes in the exam pattern of JEE Main 2022
The number of questions have increased. Out of 90 questions, the candidates can answer any 75 questions
Section B in each subject will have 10 questions out of which the candidates can answer five
There will be negative marking in Sections A & B
Out of 10 numerical questions in each section, the candidates can answer any five questions 
Name of the Subject  Total Number of Questions  Marks 
Mathematics  20 MCQ Based Questions + Ten Numerical Value Questions  100 
Physics  20 MCQ Based Questions + Ten Numerical Value Questions  100 
Chemistry  20 MCQ Based Questions + Ten Numerical Value Based Questions  100 
Total  90 Questions (75 Questions can be Answered)  300 
Name of the Section  Marking Scheme  
MCQBased Questions  Marks for Correct Answer  04 
Negative Mark for Incorrect Answer  1  
Negative Mark for Unanswered/ Marked for Review Questions  0  
Numerical Value Questions  Marks for Correct Answer  04 
Negative Mark for Incorrect Answer  Yes  
Negative Mark for Unanswered/ Marked for Review Questions  0 
If two or more candidates score the same marks in JEE Main Paper I exam, the order of merit will be determined as per the following tiebreaking rules. In order to make the candidates have a detailed understanding of tiebreaking policy, we have explained the same with some examples.
Tie Breaker 1: Candidates scoring higher marks in Mathematics will be given priority in the merit list as per tiebreaker policy  1.
Example:
Let us assume that Candidate A and Candidate B have scored 280 out of 300 in JEE Main Paper I. However, Candidate A scored 80 marks in Mathematics, while Candidate B scored 82 in Mathematics. Here, Candidate B will be given priority in the merit list as per the Tie Breaker Policy 1.
Tie Breaker 2: This policy comes into effect only if two or more candidates score the same marks in Mathematics. Since two or more candidates have similar marks in Mathematics, the marks scored by candidates in Physics will be taken into consideration to determine the merit.
Example:
Let us assume that Candidate A and Candidate B have scored 280 out of 300 in JEE Main Paper I. Both of them have also scored 80 marks in Mathematics. However, Candidate A scored 85 in Physics and Candidate B scored 82 in Physics. As per the tiebreaker policy 2, Candidate A will be given higher preference in the merit list than Candidate B.
Tie Breaker 3: This policy comes into effect only if two or more candidates score similar marks in Physics. In such cases, marks scored by candidates in Chemistry will be taken into consideration to determine the merit.
Example:
Let us assume that Candidate A and Candidate B have scored 280 out of 300 marks in JEE Main Paper I. On the other hand, both these candidates scored the same marks in the Mathematics and Physics section of the exam. However, Candidate A scored 80 marks in Chemistry and Candidate B scored 81 marks. As per tiebreaker policy 3, Candidate B will be given a higher preference in the merit list than Candidate A.
Tie Breaker 4: This policy comes into effect only if two or more candidates score the same marks in Mathematics, Physics and Chemistry sections of JEE Maine Paper I. In such cases, the candidate with less number of negative responses in the exam will be given higher preference in the order of merit.
Example:
Let us assume that Candidate A and Candidate B have scored 250 marks in JEE Main Paper I. On the other hand, both these candidates score the same marks in Mathematics, Physics and Chemistry. However, the number of wrong answers by Candidate A is 16, while the number of wrong answers by Candidate B is 18. In order to determine the merit, Candidate A will be given higher preference in the order of merit, as the number of wrong answers by Candidate A is less than Candidate B.
Tie Breaker 5: This policy comes into effect only if a tie still persists after applying all the above rules. In such cases, candidates older in age will be given higher preference in the merit list. Check the example below for a better understanding.
Example:
Let us assume that Candidate A and Candidate B scored 240 marks in JEE Main Paper I. On the other hand, these candidates scored same marks in Mathematics, Physics and Chemistry. At the same time, the number of incorrect answers by these candidates is also the same. However, Candidate A is 17 years and 6 months old and Candidate B is 17 years and 8 months old. As per tiebreaker policy 5, Candidate B will be given higher preference in the merit list.
JEE Main Paper II exam pattern 2022, marking scheme and tiebreaking policy can be checked below 
Name of the Subject  Total Number of Questions  Marks 
Mathematics Part I  20 MCQ Based Question and 10 Numerical Value Questions  100 
Aptitude Test Part II  50  200 
Drawing Test Part III  02  100 
Total  82  400 
Name of the Section  Marking Scheme  
MCQBased Questions  Marks for Correct Answer  04 
Negative Mark for Incorrect Answer  1  
Negative Mark for Unanswered/ Marked for Review Questions  0  
Numerical Value Questions  Marks for Correct Answer  04 
Negative Mark for Incorrect Answer  Yes  
Negative Mark for Unanswered/ Marked for Review Questions  0  
Drawing Test Part III  Two Questions will be evaluated for 100 marks.   
If two or more candidates secure the same marks in JEE Main Paper II exam, the below rules or tiebreaking policy will be applied to determine the merit of candidates.
Tie Breaker 1: Candidates scoring higher marks in Mathematics in JEE Main Paper II will be given preference in the merit list as per tiebreaker policy 1.
Example:
Let us assume that Candidate A and Candidate B have scored 360 out of 400 marks in JEE Main. However, Candidate A scored 79 marks in Mathematics and Candidate B scored 81 marks. The preference in the order of merit will be given to Candidate B, as he scored higher marks in Mathematics than Candidate A.
Tie Breaker 2: This policy comes into effect when two or more candidates score the same marks in Mathematics. In such cases, candidates with higher marks in the Aptitude Test will be given higher preference in the merit list.
Example:
Let us assume that Candidate A and Candidate B have scored 350 out of 400 marks in JEE Main. However, Candidate A scored 140 marks in PaperII, while Candidate B scored 139 marks. In such cases, Candidate A will be given higher preference in the order of merit than Candidate B.
Tie Breaker 3: This policy comes into effect if two or more candidates score the same marks in Mathematics and Aptitude Test. In such cases, candidates with higher marks in Drawing Test will be given preference in the order of merit.
Example:
Let us assume that Candidate A and Candidate B have scored 350 out of 400 in JEE Main PaperII. On the other hand, these candidates have also scored the same marks in Mathematics and Aptitude Test. However, Candidate A scored 78 marks on Drawing Test and Candidate B scored 80 marks. In such cases, Candidate B will be the higher preference in the merit list, as he scored higher marks in Drawing Test than Candidate A.
Tie Breaker 4: This policy comes into effect if two or more candidates score the same marks in Mathematics, Aptitude Test and Drawing Test. In such cases, candidates with fewer negative answers or incorrect answers in JEE Main PaperII exam will be given preference in the order of merit.
Example:
Let us assume that Candidate A and Candidate B have scored 250 marks in JEE Main PaperII. On the other hand, both these candidates score the same marks in Mathematics, Aptitude Test and Drawing Test. However, the number of wrong answers by Candidate A is 16, while the number of wrong answers by Candidate B is 18. In order to determine the merit, Candidate A will be given higher preference in the order of merit, as the number of wrong answers by Candidate A is less than Candidate B.
Tie Breaker 5: This policy comes into effect only if the tie still persists after applying all the above rules. In such cases, candidates older in age will be given higher preference in the merit list. Check the example below for a better understanding.
Example:
Let us assume that Candidate A and Candidate B scored 240 marks in JEE Main PaperII. On the other hand, these candidates scored the same marks in Mathematics, Aptitude Test and Drawing Test. At the same time, the number of incorrect answers by these candidates is also the same. However, Candidate A is 17 years and 6 months old and Candidate B is 17 years and 8 months old. As per tiebreaker policy 5, Candidate B will be given higher preference in the merit list.
JEE Main 2022 exam pattern for Paper III, i.e., B.Planning can be checked below 
Name of the Subject  Total Number of Questions  Marks 
Mathematics Part I  20 MCQ Based Question and Ten Numerical Value Questions  100 
Aptitude Test Part II  50  200 
Planning Based Objective Type Questions  25  100 
Total  105  400 
Name of the Section  Marking Scheme  
MCQBased Questions  Marks for Correct Answer  04 
Negative Mark for Incorrect Answer  1  
Negative Mark for Unanswered/ Marked for Review Questions  0  
Numerical Value Questions  Marks for Correct Answer  04 
Negative Mark for Incorrect Answer  Yes  
Negative Mark for Unanswered/ Marked for Review Questions  0 
If two or more candidates score the same marks in JEE Main Paper III exam, the order of merit will be determined only after applying the tiebreaking policies as mentioned below 
Tie Breaker 1: Candidates scoring higher marks in Mathematics in JEE Main Paper III will be given preference in the merit list as per tiebreaker policy 1.
Example:
Let us assume that Candidate A and Candidate B have scored 360 out of 400 marks in JEE Main Paper III. However, Candidate A scored 79 marks in Mathematics and Candidate B scored 81 marks. The preference in the order of merit will be given to Candidate B, as he/she scored higher marks in Mathematics than Candidate A.
Tie Breaker 2: This policy comes into effect when two or more candidates score the same marks in Mathematics. In such cases, candidates with higher marks in the Aptitude Test will be given higher preference in the merit list.
Example:
Let us assume that Candidate A and Candidate B have scored 350 out of 400 marks in JEE Main Paper III. However, Candidate A scored 140 marks in Paper III, while Candidate B scored 139 marks. In such cases, Candidate A will be given higher preference in the order of merit than Candidate B.
Tie Breaker 3: This policy comes into effect if two or more candidates scored the same marks in Mathematics and Aptitude Test. In such cases, the score secured by candidates in Planning Based Questions will be taken into consideration.
Example:
Let us assume that Candidate A and Candidate B have scored 350 out of 400 in JEE Main Paper III. On the other hand, these candidates have also scored the same marks in Mathematics and Aptitude Test. However, Candidate A scored 78 marks in Planning Based Questions and Candidate B scored 80 marks. In such cases, Candidate B will be given the higher preference in the merit list, as he scored higher marks in Planning Based Questions than Candidate A.
The NTA has released the syllabus of JEE Main 2022 along with the official brochure on the website. Candidates must be familiar with the JEE Main Syllabus 2022 along with the exam pattern to crack the JEE Mains. Knowledge of the JEE Main 2022 syllabus will help the student in preparing a study plan. Candidates should incorporate multiple study practices along with understand JEE Main syllabus 2022 to ace the examination. The syllabus of JEE Main 2022 is divided into three sections according to the three papers
Paper  Subjects 
JEE Main Paper 1 (BTech) 

JEE Main Paper 2A (BArch) 

JEE Main Paper 2B (BPlanning) 

As the syllabus of JEE Main exam is vast, candidates need to spend a considerable amount of time figuring out the strategy of exam preparation. JEE Main is one of the most challenging exams but with the dedication, discipline and the right preparation strategy of JEE Main 2022, candidates can surely ace the examination. A JEE Main preparation 2022 strategy along with the right approach will help the candidate in acing the JEE Main 2022.
Want to know more about JEE Main
i would suggest that you should definitely look up to JK Lakshmipat University which is situated in Jaipur. they have some really amazing faculty which teach computer engineering. there are faculty who come to the university to teach only certain course for a term or two. you get to work such exciting projects that you would to show them show them off in your resume when you sit for placements. there is huge computer lab in the university which caters to the needs of the students who want to use high end computers etc. you should definitely check the university …
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The new exam date for JEE Main April & May 2021 is expected to be announced anytime soon in June. The online registration for JEE Main May 2021 will begin after the confirmation of the exam date. As CBSE, ISC and other boards canceled the 12th exams, the government will look forward to conducting JEE Main Phase 3 & 4 as early as possible. In all probability, the exam process of JEE Main 2021 is expected to be wrapped up by August.
You can also fill the Common Application Form on our website for admissionrelated assistance. You can …
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You cannot apply for JEE Main 2021 exam as the registration process has been already closed on January 23, 2021. The application form correction is going to start from January 27 to 30, 2021.
However, you can try again for Phase 2 exam registration which will start in March 2021. You can also check JEE Main Registration to check the complete details.
Also, do not forget to check out the JEE Main Eligibility before filling up the application form.
You can also fill the Common Application Form on our website for admissionrelated assistance. You can also reach us …
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There is negative marking of 1 for MCQ based questions in JEE Main Paper 2 exam. Each wrong attempt by candidate will have a negative mark of 1
JEE Main Paper 2 exam is conducted for 400 marks.
The total number of questions in JEE Main Paper 2 exam are 82 viz., 20+10 questions from Mathematics, 50 from Aptitude and 2 from Drawing Test.
JEE Main Paper consists of three subjects, i.e., Mathematics, Aptitude Test and Drawing Test. The exam is conducted for 400 marks.
The mode of JEE Main Paper 2 exam is online (computerbased test).
JEE Main Paper 2 exam is conducted four times a year., i.e., February, March, April and May.
JEE Main Paper 2 Exam is conducted for admission in B.Arch course.