JEE Main Exam Pattern 2023 - Marking Scheme, Paper Pattern, Mode & Duration

JEE Main 2023 Exam Pattern

JEE Main exam pattern2023 has been released by NTA in the official information brochure available at jeemain.nta.nic.in 2023. The JEE Main exam pattern 2023 is carefully designed to assess a candidate's knowledge, understanding and problem-solving skills in Physics, Chemistry and Mathematics. JEE Main exam 2023 consists of two papers, Paper 1 (B Tech) and Paper 2 (B Plan & B Arch). With the exception of the drawing test for B.Arch, both papers will be administered in CBT mode in accordance with the JEE Main question paper pattern 2023.

JEE Main 2023 exam pattern paper 1 consists of 90 questions with a total of 300 marks. The MCQs are further divided into three sections – Physics, Chemistry and Mathematics. Each section comprises 20 questions, and each question carries four marks. For every wrong answer, one mark will be deducted as negative marking. Candidates will have a choice of attempting 5 out of 10 questions in the JEE Main 2023 NAT section. 

JEE Main exam pattern 2023 Paper 2 consists of a total of 82 questions across three parts – Mathematics, Aptitude Test and Drawing Test. The Mathematics section comprises 30 Questions out of which 20 are MCQ and 10 are NAT based questions, and the Aptitude Test section has 50 MCQs. The JEE Main 2023 Drawing Test section contains 2 questions for 50 marks each.

It is important for candidates to be familiar with the exam pattern and syllabus for JEE Mains 2023 before appearing for the exam to understand the type of questions asked in the exam and to improve their JEE Main 2023 preparation.

Also Read - JEE Main 2023 Preparation and Study Time Table

JEE Main Exam Pattern 2023 of Paper 1 (B.E/B.Tech)

Students should be aware of the JEE Main 2023 test pattern in order to understand the examination method, type of questions, total number of sections, marking scheme, and so on. The JEE Main 2023 exam pattern is available in the table below.

Paper 1 (B.E/B.Tech) Exam Pattern

Tie Breaking Policy for JEE Main Paper I

If two or more candidates score the same marks in JEE Main Paper I exam, the order of merit will be determined as per the following tie-breaking rules. In order to make the candidates have a detailed understanding of tie-breaking policy, we have explained the same with some examples.

Tie Breaker 1: Candidates scoring higher marks in Mathematics will be given priority in the merit list as per tie-breaker policy - 1.

Example:

Let us assume that Candidate A and Candidate B have scored 280 out of 300 in JEE Main Paper I. However, Candidate A scored 80 marks in Mathematics, while Candidate B scored 82 in Mathematics. Here, Candidate B will be given priority in the merit list as per the Tie Breaker Policy 1.

Tie Breaker 2: This policy comes into effect only if two or more candidates score the same marks in Mathematics. Since two or more candidates have similar marks in Mathematics, the marks scored by candidates in Physics will be taken into consideration to determine the merit.

Example:

Let us assume that Candidate A and Candidate B have scored 280 out of 300 in JEE Main Paper I. Both of them have also scored 80 marks in Mathematics. However, Candidate A scored 85 in Physics and Candidate B scored 82 in Physics. As per the tie-breaker policy 2, Candidate A will be given higher preference in the merit list than Candidate B.

Tie Breaker 3: This policy comes into effect only if two or more candidates score similar marks in Physics. In such cases, marks scored by candidates in Chemistry will be taken into consideration to determine the merit.

Example:

Let us assume that Candidate A and Candidate B have scored 280 out of 300 marks in JEE Main Paper I. On the other hand, both these candidates scored the same marks in the Mathematics and Physics section of the exam. However, Candidate A scored 80 marks in Chemistry and Candidate B scored 81 marks. As per tie-breaker policy 3, Candidate B will be given a higher preference in the merit list than Candidate A.

Tie Breaker 4: This policy comes into effect only if two or more candidates score the same marks in Mathematics, Physics and Chemistry sections of JEE Maine Paper I. In such cases, the candidate with less number of negative responses in the exam will be given higher preference in the order of merit.

Example:

Let us assume that Candidate A and Candidate B have scored 250 marks in JEE Main Paper I. On the other hand, both these candidates score the same marks in Mathematics, Physics and Chemistry. However, the number of wrong answers by Candidate A is 16, while the number of wrong answers by Candidate B is 18. In order to determine the merit, Candidate A will be given higher preference in the order of merit, as the number of wrong answers by Candidate A is less than Candidate B.

Tie Breaker 5: This policy comes into effect only if a tie still persists after applying all the above rules. In such cases, candidates older in age will be given higher preference in the merit list. Check the example below for a better understanding.

Example:

Let us assume that Candidate A and Candidate B scored 240 marks in JEE Main Paper I. On the other hand, these candidates scored same marks in Mathematics, Physics and Chemistry. At the same time, the number of incorrect answers by these candidates is also the same. However, Candidate A is 17 years and 6 months old and Candidate B is 17 years and 8 months old. As per tie-breaker policy 5, Candidate B will be given higher preference in the merit list.

JEE Main 2023 Exam Pattern for Paper 2 (B Arch & B Plan)

The JEE Main 2023 B Arch and B Plan is conducted in Computer Based Test mode with the exception of the drawing section which will be done as a pen and paper based test on an A4 paper. The Section 1 tests the candidate's mathematical ability whereas section 2 is based on Aptitute. JEE Main Paper II exam pattern 2023, marking scheme and tie-breaking policy can be checked below -

JEE Main 2023 Exam Pattern: Paper 2B (B.Plan)

Tie Breaking Policy for JEE Main Paper II

If two or more candidates secure the same marks in JEE Main Paper II exam, the below rules or tie-breaking policy will be applied to determine the merit of candidates.

Tie Breaker 1:Candidates scoring higher marks in Mathematics in JEE Main Paper II will be given preference in the merit list as per tie-breaker policy 1.

Example:

Let us assume that Candidate A and Candidate B have scored 360 out of 400 marks in JEE Main. However, Candidate A scored 79 marks in Mathematics and Candidate B scored 81 marks. The preference in the order of merit will be given to Candidate B, as he scored higher marks in Mathematics than Candidate A.

Tie Breaker 2: This policy comes into effect when two or more candidates score the same marks in Mathematics. In such cases, candidates with higher marks in the Aptitude Test will be given higher preference in the merit list.

Example:

Let us assume that Candidate A and Candidate B have scored 350 out of 400 marks in JEE Main. However, Candidate A scored 140 marks in Paper-II, while Candidate B scored 139 marks. In such cases, Candidate A will be given higher preference in the order of merit than Candidate B.

Tie Breaker 3: This policy comes into effect if two or more candidates score the same marks in Mathematics and Aptitude Test. In such cases, candidates with higher marks in Drawing Test will be given preference in the order of merit.

Example:

Let us assume that Candidate A and Candidate B have scored 350 out of 400 in JEE Main Paper-II. On the other hand, these candidates have also scored the same marks in Mathematics and Aptitude Test. However, Candidate A scored 78 marks on Drawing Test and Candidate B scored 80 marks. In such cases, Candidate B will be the higher preference in the merit list, as he scored higher marks in Drawing Test than Candidate A.

Tie Breaker 4: This policy comes into effect if two or more candidates score the same marks in Mathematics, Aptitude Test and Drawing Test. In such cases, candidates with fewer negative answers or incorrect answers in JEE Main Paper-II exam will be given preference in the order of merit.

Example:

Let us assume that Candidate A and Candidate B have scored 250 marks in JEE Main Paper-II. On the other hand, both these candidates score the same marks in Mathematics, Aptitude Test and Drawing Test. However, the number of wrong answers by Candidate A is 16, while the number of wrong answers by Candidate B is 18. In order to determine the merit, Candidate A will be given higher preference in the order of merit, as the number of wrong answers by Candidate A is less than Candidate B.

Tie Breaker 5: This policy comes into effect only if the tie still persists after applying all the above rules. In such cases, candidates older in age will be given higher preference in the merit list. Check the example below for a better understanding.

Example:

Let us assume that Candidate A and Candidate B scored 240 marks in JEE Main Paper-II. On the other hand, these candidates scored the same marks in Mathematics, Aptitude Test and Drawing Test. At the same time, the number of incorrect answers by these candidates is also the same. However, Candidate A is 17 years and 6 months old and Candidate B is 17 years and 8 months old. As per tie-breaker policy 5, Candidate B will be given higher preference in the merit list.

JEE Main 2023 Marking Scheme (B Tech, BArch & B Plan)

The JEE Main marking scheme 2023 for MCQ and NAT section is the same, the differentiating factor being MCQ has 4 options out of which one is correct whereas NAT section requires an integer number to be inputted. The JEE Main 2023 drawing section is analyzed, since the section is analytical and logical in nature, candidates will be assessed and marked based on their capabilities. There is no particular negative marking for the Drawing section.