## Tie Breaking Policy for JEE Main Paper I

If two or more candidates score the same marks in JEE Main Paper I exam, the order of merit will be determined as per the following tie-breaking rules. In order to make the candidates have a detailed understanding of tie-breaking policy, we have explained the same with some examples.

__Tie Breaker 1: __Candidates scoring higher marks in Mathematics will be given priority in the merit list as per tie-breaker policy - 1.

__Example: __

Let us assume that Candidate A and Candidate B have scored 280 out of 300 in JEE Main Paper I. However, Candidate A scored 80 marks in Mathematics, while Candidate B scored 82 in Mathematics. Here, Candidate B will be given priority in the merit list as per the Tie Breaker Policy 1.

__Tie Breaker 2: __This policy comes into effect only if two or more candidates score the same marks in Mathematics. Since two or more candidates have similar marks in Mathematics, the marks scored by candidates in Physics will be taken into consideration to determine the merit.

__Example:__

Let us assume that Candidate A and Candidate B have scored 280 out of 300 in JEE Main Paper I. Both of them have also scored 80 marks in Mathematics. However, Candidate A scored 85 in Physics and Candidate B scored 82 in Physics. As per the tie-breaker policy 2, Candidate A will be given higher preference in the merit list than Candidate B.

__Tie Breaker 3: __This policy comes into effect only if two or more candidates score similar marks in Physics. In such cases, marks scored by candidates in Chemistry will be taken into consideration to determine the merit.

__Example:__

Let us assume that Candidate A and Candidate B have scored 280 out of 300 marks in JEE Main Paper I. On the other hand, both these candidates scored the same marks in the Mathematics and Physics section of the exam. However, Candidate A scored 80 marks in Chemistry and Candidate B scored 81 marks. As per tie-breaker policy 3, Candidate B will be given a higher preference in the merit list than Candidate A.

__Tie Breaker 4: __This policy comes into effect only if two or more candidates score the same marks in Mathematics, Physics and Chemistry sections of JEE Maine Paper I. In such cases, the candidate with less number of negative responses in the exam will be given higher preference in the order of merit.

__Example:__

Let us assume that Candidate A and Candidate B have scored 250 marks in JEE Main Paper I. On the other hand, both these candidates score the same marks in Mathematics, Physics and Chemistry. However, the number of wrong answers by Candidate A is 16, while the number of wrong answers by Candidate B is 18. In order to determine the merit, Candidate A will be given higher preference in the order of merit, as the number of wrong answers by Candidate A is less than Candidate B.

__Tie Breaker 5: __This policy comes into effect only if a tie still persists after applying all the above rules. In such cases, candidates older in age will be given higher preference in the merit list. Check the example below for a better understanding.

__Example:__

Let us assume that Candidate A and Candidate B scored 240 marks in JEE Main Paper I. On the other hand, these candidates scored same marks in Mathematics, Physics and Chemistry. At the same time, the number of incorrect answers by these candidates is also the same. However, Candidate A is 17 years and 6 months old and Candidate B is 17 years and 8 months old. As per tie-breaker policy 5, Candidate B will be given higher preference in the merit list.