JEE Main 2020 Exam Pattern

Sakunth Kumar Updated On: 07 Jan, 2020 12:31 IST

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JEE Main 2020 Exam Pattern (New)

JEE Main exam pattern for 2020 has been revised, and the new pattern for the same is now available. 2020 JEE Main aspirants should note that entrance exam will be conducted as per the revised pattern, and it is advisable to check the same carefully. So far, there have been only two papers in JEE Main, and from the year 2020, there will be three papers in the JEE Main exam. JEE Main Paper III, i.e., for Bachelor's in Planning (B.Planning) has been introduced as a new paper in Mains exam 2020. The detailed information about the changes in the exam pattern of IIT JEE Mains along with the marking scheme and tie-breaking policy can be checked below.

Overview of Major Changes in JEE Main Exam Pattern 2020

Here are some of the major changes in the exam pattern -

  • Paper III has been introduced in JEE Main 2020, and the respective paper is conducted for the admission in B.Planning course.
  • Paper III is conducted for 400 marks.
  • The total number of questions in Paper III is 100
  • The subjects included in JEE Main Paper III exam are Mathematics, Aptitude Test and Planning Based Objective Questions.
  • Negative marking is applicable for only MCQ-based questions in Paper III

JEE Main Exam Pattern 2020 for Paper I (B.E/ B.Tech)

The JEE Main Paper I exam pattern 2020 can be checked below -

Name of the Subject

Total Number of Questions

Marks

Mathematics

20 MCQ Based Questions + Five Numerical Value Questions

100

Physics

20 MCQ Based Questions + Five Numerical Value Questions

100

Chemistry

20 MCQ Based Questions + Five Numerical Value Based Questions

100

Total

75 Questions

300

Marking Scheme for JEE Main Paper I

Name of the Section

Marking Scheme

MCQ-Based Questions

 

Marks for Correct Answer

 

04

Negative Mark for Incorrect Answer

-1

Negative Mark for Unaswered/ Marked for Review Questions

0

Numerical Value Questions

Marks for Correct Answer

 

04

Negative Mark for Incorrect Answer

0

Negative Mark for Unaswered/ Marked for Review Questions

0

Tie Breaking Policy for JEE Main Paper I

If two or more candidates score the same marks in JEE Main Paper I exam, the order of merit will be determined as per the following tie-breaking rules. In order to make the candidates have a detailed understanding of tie-breaking policy, we have explained the same with some examples.

Tie Breaker 1: Candidates scoring higher marks in Mathematics will be given priority in the merit list as per tie-breaker policy - 1.

Example:

Let us assume that Candidate A and Candidate B have scored 280 out of 300 in JEE Main Paper I. However, Candidate A scored 80 marks in Mathematics, while Candidate B scored 82 in Mathematics. Here, Candidate B will be given priority in the merit list as per the Tie Breaker Policy 1.

Tie Breaker 2: This policy comes into effect only if two or more candidates score the same marks in Mathematics. Since two or more candidates have similar marks in Mathematics, the marks scored by candidates in Physics will be taken into consideration to determine the merit.

Example:

Let us assume that Candidate A and Candidate B have scored 280 out of 300 in JEE Main Paper I. Both of them have also scored 80 marks in Mathematics. However, Candidate A scored 85 in Physics and Candidate B scored 82 in Physics. As per the tie-breaker policy 2, Candidate A will be given higher preference in the merit list than Candidate B.

Tie Breaker 3: This policy comes into effect only if two or more candidates score similar marks in Physics. In such cases, marks scored by candidates in Chemistry will be taken into consideration to determine the merit.

Example:

Let us assume that Candidate A and Candidate B have scored 280 out of 300 marks in JEE Main Paper I. On the other hand, both these candidates scored same marks in Mathematics and Physics section of the exam. However, Candidate A scored 80 marks in Chemistry and Candidate B scored 81 marks. As per tie-breaker policy 3, Candidate B will be given higher preference in merit list than Candidate A.

Tie Breaker 4: This policy comes into effect only if two or more candidates score same marks in Mathematics, Physics and Chemistry sections of JEE Maine Paper I. In such cases, the candidate with less number of negative responses in the exam will be given higher preference in the order of merit.

Example:

Let us assume that Candidate A and Candidate B have scored 250 marks in JEE Main Paper I. On the other hand, both these candidates scores same marks in Mathematics, Physics and Chemistry. However, the number of wrong answers by Candidate A is 16, while the number of wrong answers by Candidate B is 18. In order to determine the merit, Candidate A will be given higher preference in the order of merit, as the number of wrong answers by Candidate A is less than Candidate B.

Tie Breaker 5: This policy comes into effect only if a tie still persists after applying all the above rules. In such cases, candidates older in age will be given higher preference in the merit list. Check the example below for a better understanding.

Example:

Let us assume that Candidate A and Candidate B scored 240 marks in JEE Main Paper I. On the other hand, these candidates scored same marks in Mathematics, Physics and Chemistry. At the same time, the number of incorrect answers by these candidates is also the same. However, Candidate A is 17 years and 6 months old and Candidate B is 17 years and 8 months old. As per tie-breaker policy 5, Candidate B will be given higher preference in the merit list.

JEE Main 2020 Exam Pattern for Paper II (B.Arch)

JEE Main Paper II exam pattern 2020, marking scheme and tie-breaking policy can be checked below -

Name of the Subject

Total Number of Questions

Marks

Mathematics Part I

20 MCQ Based Question and Five Numerical Value Questions

100

Aptitude Test Part II

50

200

Drawing Test Part III

02

100

Total

77

400

Marking Scheme for JEE Main Paper II

Name of the Section

Marking Scheme

MCQ-Based Questions

Marks for Correct Answer

04

Negative Mark for Incorrect Answer

-1

Negative Mark for Unaswered/ Marked for Review Questions

0

Numerical Value Questions

Marks for Correct Answer

 

04

Negative Mark for Incorrect Answer

0

Negative Mark for Unaswered/ Marked for Review Questions

0

Drawing Test Part III

Two Questions will be evaluated for 100 marks.

-

Tie Breaking Policy for JEE Main Paper II

If two or more candidates secure the same marks in JEE Main Paper II exam, the below rules or tie-breaking policy will be applied to determine the merit of candidates.

Tie Breaker 1: Candidates scoring higher marks in Mathematics in JEE Main Paper II will be given preference in the merit list as per tie-breaker policy 1.

Example:

Let us assume that Candidate A and Candidate B have scored 360 out of 400 marks in JEE Main. However, Candidate A scored 79 marks in Mathematics and Candidate B scored 81 marks. The preference in the order of merit will be given to Candidate B, as he scored higher marks in Mathematics than Candidate A.

Tie Breaker 2: This policy comes into effect when two or more candidates score the same marks in Mathematics. In such cases, candidates with higher marks in the Aptitude Test will be given higher preference in the merit list.

Example:

Let us assume that Candidate A and Candidate B have scored 350 out of 400 marks in JEE Main. However, Candidate A scored 140 marks in Paper-II, while Candidate B scored 139 marks. In such cases, Candidate A will be given higher preference in the order of merit than Candidate B.

Tie Breaker 3: This policy comes into effect if two or more candidates score the same marks in Mathematics and Aptitude Test. In such cases, candidates with higher marks in Drawing Test will be given preference in the order of merit.

Example:

Let us assume that Candidate A and Candidate B have scored 350 out of 400 in JEE Main Paper II. On the other hand, these candidates have also scored the same marks in Mathematics and Aptitude Test. However, Candidate A scored 78 marks in Drawing Test and Candidate B scored 80 marks. In such cases, Candidate B will be the higher preference in the merit list, as he scored higher marks in Drawing Test than Candidate A.

Tie Breaker 4: This policy comes into effect if two or more candidates score the same marks in Mathematics, Aptitude Test and Drawing Test. In such cases, candidates with the less number of negative answers or incorrect answers in JEE Main Paper-II exam will be given preference in the order of merit.

Example:

Let us assume that Candidate A and Candidate B have scored 250 marks in JEE Main Paper II. On the other hand, both these candidates scores same marks in Mathematics, Aptitude Test and Drawing Test. However, the number of wrong answers by Candidate A is 16, while the number of wrong answers by Candidate B is 18. In order to determine the merit, Candidate A will be given higher preference in the order of merit, as the number of wrong answers by Candidate A is less than Candidate B.

Tie Breaker 5: This policy comes into effect only if the tie still persists after applying all the above rules. In such cases, candidates older in age will be given higher preference in the merit list. Check the example below for a better understanding.

Example:

Let us assume that Candidate A and Candidate B scored 240 marks in JEE Main Paper II. On the other hand, these candidates scored same marks in Mathematics, Aptitude Test and Drawing Test. At the same time, the number of incorrect answers by these candidates is also the same. However, Candidate A is 17 years and 6 months old and Candidate B is 17 years and 8 months old. As per tie-breaker policy 5, Candidate B will be given higher preference in the merit list.

JEE Main Exam Pattern 2020 for Paper III (B.Planning)

JEE Main exam pattern 2020 for Paper III, i.e., B.Planning can be checked below -

Name of the Subject

Total Number of Questions

Marks

Mathematics Part I

20 MCQ Based Question and Five Numerical Value Questions

100

Aptitude Test Part II

50

200

Planning Based Objective Type Questions

25

100

Total

100

400

 

Marking Scheme for JEE Main Paper III

Name of the Section

Marking Scheme

MCQ-Based Questions

Marks for Correct Answer

04

Negative Mark for Incorrect Answer

-1

Negative Mark for Unaswered/ Marked for Review Questions

0

Numerical Value Questions

Marks for Correct Answer

 

04

Negative Mark for Incorrect Answer

0

Negative Mark for Unaswered/ Marked for Review Questions

0

Tie Breaking Policy for JEE Main Paper III

If two or more candidates score the same marks in JEE Main Paper III exam, the order of merit will be determined only after applying the tie-breaking policies as mentioned below -

Tie Breaker 1: Candidates scoring higher marks in Mathematics in JEE Main Paper III will be given preference in the merit list as per tie-breaker policy 1.

Example:

Let us assume that Candidate A and Candidate B have scored 360 out of 400 marks in JEE Main Paper III. However, Candidate A scored 79 marks in Mathematics and Candidate B scored 81 marks. The preference in the order of merit will be given to Candidate B, as he/she scored higher marks in Mathematics than Candidate A.

Tie Breaker 2: This policy comes into effect when two or more candidates score the same marks in Mathematics. In such cases, candidates with higher marks in the Aptitude Test will be given higher preference in the merit list.

Example:

Let us assume that Candidate A and Candidate B have scored 350 out of 400 marks in JEE Main Paper III. However, Candidate A scored 140 marks in Paper III, while Candidate B scored 139 marks. In such cases, Candidate A will be given higher preference in the order of merit than Candidate B.

Tie Breaker 3: This policy comes into effect if two or more candidates scored the same marks in Mathematics and Aptitude Test. In such cases, the score secured by candidates in Planning Based Questions will be taken into consideration.

Example:

Let us assume that Candidate A and Candidate B have scored 350 out of 400 in JEE Main Paper III. On the other hand, these candidates have also scored the same marks in Mathematics and Aptitude Test. However, Candidate A scored 78 marks in Planning Based Questions and Candidate B scored 80 marks. In such cases, Candidate B will be given the higher preference in the merit list, as he scored higher marks in Planning Based Questions than Candidate A.

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