TS ICET 2025 Mensuration Weightage & Sample Questions

Knowing the TS ICET 2025 Mensuration Weightage & Sample Questions can provide you with a significant advantage in the Mathematical Ability section. As one of the most significant parts of the Arithmetical Ability section, Mensuration contains approximately 5 questions that will present a possibility of including 5 marks. Mensuration concepts are a section of the Mathematical Ability section of the test, and the Algebraical and Geometrical Ability sub-section. This section is designed to assess your ability to learn and apply formulas related to the area and volume of certain shapes in 2D space and 3D space. The Mathematical Ability section encompasses various parts, including percentage, time and work, coordinate geometry, probability, and many more to assess quantitative and logical capability on the part of the candidates. This section will include 75 questions in all, as Arithmetical Ability (35 questions), Algebraical & Geometrical Ability (30 questions), and Statistical Ability (10 questions). Practicing mensuration based problems can drastically help improve accuracy and scoring potential on the TS ICET 2025 exam.

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TS ICET 2025 Mensuration Weightage

Mensuration is an important topic under the Mathematical Ability section of TS ICET 2025 . According to the latest exam pattern, it is analysed that total 5 questions on Mensuration can be asked, which carry a total of 5 marks. The table below presents the number of questions on Mensuration and corresponding marks, which should help you prioritize Mensuration while preparing.

Also Read: TS ICET 2025 Reading Comprehension Weightage & Sample Questions

TS ICET 2025 Mensuration Sample Questions

To help candidates prepare for the test, we have included a range of sample questions that reflect the degree of difficulty and types of problems commonly seen in the Mensuration portion of the TS ICET 2025. The practice questions focus not only on everyday analyses of area, volume, surface area, and perimeter of standard geometric shapes -- rectangles, circles, spheres, cones, cylinders, and prisms -- but also on how to employ formulas to help students understand basic geometry and enhance problem-solving skills. Each question includes a complete solution. Make sure to practice these questions fully to help with speed and accuracy during the test!

Question 1: The ratio of length and breadth of a rectangle is 5:3. The Diameter of the circle is 7/5 of the length of a rectangle. The circumference of the circle is 24 m more than the perimeter of the rectangle. What is the area of a rectangle?

a) 340

b) 280

c) 216

d) 240

e) 220

Answer: d) 240

Explanation: Let length = 5x Breadth = 3x Diameter of circle = (7/5) × 5x = 7x Radius = 7x/2 Circumference = 2πr = 2 × (22/7) × (7x/2) = 22x Perimeter of rectangle = 2(5x + 3x) = 16x

Given : 22x =16x + 24 ⇒ 6x = 24 ⇒ x = 4

Length = 20 Breadth = 12 Area = 20 × 12 = 240m^2

Question 2: What is the radius of a sphere that has a volume of 38808 cm3? (Use π = 22/7)

a) 21 cm

b) 27 cm

c) 24 cm

d) 18 cm

e) 9

Answer : 21 cm

Explanation: volume of a sphere, (V) = 38808 cm3

Formula used: volume of a sphere,

V = (4/3)πr3 where, r = radius

Calculation step: 38808 = (4/3) × (22/7) × r3 ⇒ 38808 = (88/21) × r3 ⇒ r3 = 38808 × (21/88) ⇒ r3 = 9261    ⇒ r = 21 cm

Hence, the answer to the above question is option 1

Question 3: If the perimeter of the circle equals 66m, which is 3/4th of actual perimeter of the circle. What is the area of the circle.

a) 616 m2

b) 512 m2

c) 343 m2

d) 589 m2

e) 215 m2

Answer: 616 m2

Explanation: The perimeter (circumference) of the circle is 66 m, which is 3/4th of the actual perimeter of the circle.

Formula used: Perimeter (Circumference) of circle = 2πr. Let the actual perimeter of the circle be C.

We have: 3C/4 = 66.

Solving the equation for C,

lets multiply both sides by 4/3: C = 66 x 4/3 = 88 m Now using the actual given perimeter C = 2πr,

let's find the radius: 88 = 2 x 22/7 x r r = (88 × 7)(2×22) = 616/44= 14 m

Now using the concept of area of a circle A = πr^2: A = 22/7 × 14^2 A = 22/7 × 196 = 4312/7 = 616 m2

Area of the circle = 616 m².

Question 4: In measuring the sides of a rectangle, one side is taken as 10% in excess, and the other is taken as 8% in deficit. Hence error percent in the area found by these measurements is:

a) 1.4%

b) 1.0%

c) 1.2%

d) None of these

Answer: 1.2%

Explanation: In measuring the sides of a rectangle, one side is taken as 10% in excess, and the other side is taken as 8% in deficit.

Formula: Error Percent in Area =

(Percentage Error in Length + Percentage Error in Width + Percentage Error in Length x Percentage Error in Width )

Let the actual length L, and the actual width W. Measured Length = L + 0.10L = 1.1L Measured Width = W - 0.08W = 0.92W Error in Length = 10% Error in Width = -8% Percentage Error in Area = 10% + (-8%) + (0.10)(-0.08) =

Percentage Error in Area = 10 - 8 = (0.10)(-0.08) =

Percentage Error in Area = 2 - 0.8% =

Percentage Error in Area = 1.2%

Final Answer: option (3)

Question 5: The length and width of a rectangle measure 25 cm and 15 cm respectively. What is the area of the rectangle?

A) 360 cm²

B) 375 cm²

C) 385 cm²

D) 390 cm²

Answer: B) 375 cm²

Explanation: Area = Length × Width = 25 × 15 = 375 cm²

Question 6. A cone has a radius of 4 cm and a height of 9 cm. Find the volume of this cone.

A) 150.5 cm³

B) 140.8 cm³

C) 160.2 cm³

D) 150.72 cm³

Answer: D) 150.72 cm³

Explanation: Volume = (1/3)πr²h = (1/3) × (22/7) × 4² × 9 = ~150.72 cm³

Question 7. The diameter of a sphere is 14 cm. Calculate the surface area.

A) 616 cm²

B) 624 cm²

C) 628 cm²

D) 636 cm²

Answer: A) 616 cm²

Explanation: Surface area = 4πr² = 4 × (22/7) × 7 × 7 = 616 cm

Question 8. How to find the lateral surface area of a cylinder whose radius is 5 cm and height is 10 cm.

A) 310 cm²

B) 314 cm²

C) 312 cm²

D) 316 cm²

Answer: B) 314 cm²

Explanation: Lateral surface area = 2πrh = 2 × (22/7) × 5 × 10 = 314 cm²

Question 9. If the base area of a prism is 50 cm² and its height is 12 cm. What is the prism's volume?

A) 600 cm³

B) 620 cm³

C) 580 cm³

D) 590 cm³

Answer: A) 600 cm³

Explanation: Volume = Base area × Height = 50 × 12 = 600 cm³

Question 10. A hemisphere has a radius of 3 cm. What is its total surface area?

A) 84.57 cm²

B) 85.5 cm²

C) 94.2 cm²

D) 96.3 cm²

Answer: C) 94.2 cm²

Explanation: Total surface area = 3πr² = 3 × (22/7) × 3² = 94.2 cm²

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TS ICET 2025 Mensuration Preparation Tips

Mensuration is an essential unit under the Mathematical Ability section of the TS ICET 2025 exam. Weighing 5 marks, it will consist of 5 questions exclusively on this topic. To do well in Mensuration, you need to be familiar with formulas, conversions of units, and efficient ways to solve calculations. By using a proper method and practicing often, your speed and accuracy can be improved greatly. Here are some helpful preparation strategies to assist you with Mensuration questions in TS ICET 2025.

• Learn the Basic Formulas: Mensuration questions require formulas connected to area, perimeter, surface area, and volume related to 2D and 3D shapes. You should focus on learning about Rectangles, squares, triangles, circles, Cubes, cuboids, cylinders, cones, spheres, hemispheres, and finally, plan a formula sheet and go over it daily.
• Understand Unit Conversion: Be sure you can convert between units such as  cm² to m², m² to liters, etc., as these are overtested in exams.
• Solve Concept-Related Problems: Make sure you can apply formulas using their real-counted shapes, and practice applying formulas using composite figures. For example, adding a cone to a certain figure.
• Solve Previous Year Questions: Attempt previous TS ICET question papers and mock tests overall to get to terms with the mensuration questions that may come in the respective exam. You want to be cognizant of the type and difficulty of mensuration questions from the exam.
• Increase Speed: As mensuration will come out in decimal and fraction formats, mental math but important, is time-consuming. Practicing to your knowledge of multiplication tables, square or cube value, etc., may help you reduce time spent on fractions as well as decimals
• Visualization is Key: Mensuration is much easier when you can visualize the shape, so if you are working on complex problems, make sure to jot down some sketchy diagrams.
• Time Yourself: Time yourself on mensuration questions when you are practicing some questions to ensure you can be quick and accurate under exam pressure.
• Apply Nifty Tricks: Learn and use nifty tricks where applicable - especially if you are dealing with common figures such as cylinders, spheres, and cones.

Familiarizing yourself with the TS ICET 2025 Mensuration Weightage & Sample Questions can help you with your exam preparedness in the Mathematical Ability section of the TS ICET 2025 exam. Mensuration is an important component of the Mathematical Ability area in the TS ICET 2025 exam. As Mensuration is a topic that regularly appears in the exam and features direct formula problem solving, a clear understanding of the subject can pay dividends in your overall grade. By practicing various sample problems and refreshing yourself on the formulas for both 2D and 3D shapes, you will be able to work more effectively and confidently in the exam.  This is a topic worth investing your efforts in to be ahead of the game in your TS ICET 2025 preparation process.

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