KURMA SANSKRITI INSTITUTE OF PHARMACEUTICAL SCIENCE,JEHANABAD B.Com fees is 50,000 INR (Yearly). KURMA SANSKRITI INSTITUTE OF PHARMACEUTICAL SCIENCE,JEHANABAD B.Com admission 2024 will be based on CUET.
Course | Duration | Fees |
B.Com (Professional) | 3 Years | 50000 INR |
To pursue a Bachelor of Commerce (B.Com.) degree at Kurma Sanskriti Institute of Pharmaceutical Science in Jehanabad, candidates must meet certain eligibility criteria. Applicants should have completed their higher secondary education (10+2) from a recognized board or its equivalent, with a minimum aggregate score of 50%. Additionally, they should have studied commerce or a related subject in their 10+2 curriculum. Candidates from any stream are eligible to apply, as long as they fulfill the aforementioned criteria. Admissions are based on merit, and candidates may also need to appear for an entrance examination or interview conducted by the institute.
Admission to the B.Com at KURMA SANSKRITI INSTITUTE OF PHARMACEUTICAL SCIENCE,JEHANABAD is subject to meeting the eligibility criteria and the candidates have to secure a valid score in CUET. All shortlisted candidates have to complete the KURMA SANSKRITI INSTITUTE OF PHARMACEUTICAL SCIENCE,JEHANABAD B.Com admission process by getting their documents verified and paying the admission fee.
Event Name | Date |
Exam Date | 15 May 2024 - 31 May 2024 |
KURMA SANSKRITI INSTITUTE OF PHARMACEUTICAL SCIENCE,JEHANABAD B.Com application form has to be submitted online by visiting the official website. Candidates aspiring to take admission to the B.Com course at KURMA SANSKRITI INSTITUTE OF PHARMACEUTICAL SCIENCE,JEHANABAD have to first check and meet the eligibility criteria and then proceed further with the application process.