NEET Gibbs Energy Change Practice Questions With Solutions

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NEET Chemistry Gibbs Energy Change Practice Questions

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Question 1.

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A process among the following shows decrease in entropy is :

Question 2.

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For a given reaction, ∆H = 35.5 kJ mol–1 and ∆S = 83.6 J K–1 mol–1. The reaction is spontaneous at: (Assume that ∆H and ∆S  do not vary with temperature)

Question 3.

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The correct thermodynamic conditions for a spontaneous reaction at all temperatures is:

Question 4.

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In which of the following reactions, the standard reaction entropy change
(S0) is positive, and standard Gibb's energy change
(G0) decreases sharply with increasing temperature?

Question 5.

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For vaporization of water at 1 atmospheric pressure, the values of ∆H and ∆S are 40.63 kJ mol–1 and 108.8 JK–1 mol–1, respectively. The temperature when Gibbs energy change (∆G) for this transformation will be zero, is:

Question 6.

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Standard entropies of X2, Y2 and XY3 are 60, 40 and 50JK-1mol-1 respectively. For the reaction 
12X2+32Y2XY3;H=-30kJ to be at equilibrium, the temperature should be:

Question 7.

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Which of the following are not state functions? (I) q + W (II) q (III) W (IV) H - TS

Question 8.

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Which of the following statements about the advantage of roasting sulphide ore before reduction is not true?
1.Carbon and hydrogen act as suitable reducing agents for metal sulphides
2.The \(\Delta_f G^0\) of the sulphide is greater than those for \(C S_2\) and \(\mathrm{H}_2 \mathrm{~S}\)
3.The \(\Delta_f G^0\) is negative for roasting of sulphur ore to oxide.
4.Roasting of the sulphide to the oxide is thermodynamically feasible

Question 9.

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The enthalpy and entropy change for the reaction: Br2 (l) + Cl2 (g) →2BrCl(g), are 30kJ mol-1 and 105 JK-1 mol-1 respectively. The temperature at which the reaction will be in equilibrium is:

Question 10.

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The standard enthalpy and standard entropy changes for the oxidation of ammonia at 298 K are –382.64 kJ mol–1 and –145.6 JK–1 mol–1, respectively. Standard Gibbs energy change for the same reaction at 298 K is:
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Question 1.

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2Zn+O22ZnOG°=-616J
2Zn+S22ZnSG°=-293J
S2+2O22SO2G°=-408JG° for the following reaction is: 2ZnS+3O22ZnO+2SO2

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