MHT CET Previous Year Question Papers with Solutions and Answer Keys PDF

MHT CET Previous Year Question Papers

MHT CET Previous Year Question Paper is available here in the form of PDFs. Candidates preparing for the MHT CET exam 2026 must go through the MHT CET previous year question papers to ensure the best preparation for the MHT CET exam. The previous year's question papers will provide the candidates with insights into the exam, like the exam pattern, important topics, weightage of topics, important questions, etc. Practising the MHT CET previous years' question papers PCM will help the students enhance their time management skills and accuracy in solving the questions. 

JEE Question Papers will also help aspiring candidates to know the detailed MHT CET 2026 Exam Pattern and other aspects of the questions, like specific topics that are important in the exam. MHT CET question paper PDFs become crucial as they are a very important part of the MHT CET 2026 preparation. Candidates are also advised to go through the MHT CET preparation tips along with the question papers, as they will help them develop a good strategy for the exam. Check the MHT CET 2026 question paper PDF for download on the page below.

Sample MHT CET 2026 Question Paper

If you are an aspirant of the MHT CET 2026 Exam, candidates can check and practice the MHT CET 2026 Question Paper PDF below:

MHT CET Previous Years Question Papers: Free Download

Candidates can download the MHT CET Previous Year Question Paper PDF from the table below. To download the MHT CET Previous Year Papers, candidates have to merely click the question paper link, and the PDF will be available for download:

How to Download the MHT CET Previous Year Question Papers?

The CET Cell Maharashtra does not release the MHT CET question papers separately; the registered candidates can only download the response sheet that will contain the questions asked in the MHT CET exam. Check the steps to download the MHT CET previous year's question papers/response sheet below:

• Go to the official website 

• Click on the MHT CET provisional answer key link 

• Log in to the registered account 

• The response sheet/question paper will appear on the screen 

• Download the MHT CET previous years question papers PCM and save them for later use

How To Solve MH CET Previous Year Papers?

The purpose of solving the previous year papers of MHT CET is to improve the overall test-taking strategy used by the candidates. As candidates solve MHT CET previous year papers, their level of accuracy increases enabling them to finish the paper on time.

1. Allocate two separate time slots of 90 minutes each for the two papers of MHT CET.
2. Begin with your strong subject (for Paper 2). If Mathematics is your strongest subject, start with it.
3. Carefully go through all the questions as they appear and try to understand whether or not you will be able to solve them.
4. Attempt only those questions that you are 100% sure about. Skip the rest.
5. For questions that you are not fully sure about but you think you should give a shot, mark them.
6. Once you have gone through the entire paper and answered all the questions that you are sure about, try to attempt the marked questions. Then try the next level of questions, and so on.
7. Do not spend too much time on any question, nor answer any question in a hurry.

Check MHT CET Mock Test 2026

MHT CET 2026: Important Topics

Candidates preparing from the MHT CET previous year's question paper PDF must check the subject-wise important topics, which are repeated almost every year.  Check the important topics for the MHT CET 2026 exam in the table below:

Advantages of Solving MHT CET Previous Years’ Question Papers

Mentioned below are some of the advantages of solving MHT CET previous years’ question papers/sample paper:

• With the help of MHT CET previous years’ question papers/sample paper, candidates can get an idea of the MHT CET exam pattern, type and nature of questions that are asked in the entrance exam, and candidates will also be able to practice the different type of questions

• By taking MHT CET previous years’ question papers/sample paper, candidates can improve their question-solving ability, speed, and time-management skills

• Through solving MHT CET previous year papers with solutions, candidates can analyze their strong and weak areas

• Candidates preparing for the exam can use the MHT CET old question papers as a reference to know the MHT CET previous year papers marking scheme of each section and questions

• Most importantly solving MHT CET sample papers and previous years’ question papers give the candidates the feel of solving the actual exam and are the only source of quality practice which is required to face the exams

MHT CET Practice Questions For PCM & PCB

Practice MHT CET 2026 PCM and PCB practice questions from the following questions.

Physics

Question 1:

A body is projected vertically upwards with a velocity of 20 m/s. The maximum height reached by the body is:

(a) 10 m (b) 20 m (c) 30 m (d) 40 m

Solution:

We can use the following equation of motion to solve this problem:

v^2 = u^2 + 2as

where:

• v = final velocity (0 m/s at the maximum height)
• u = initial velocity (20 m/s)
• a = acceleration due to gravity (-10 m/s^2)
• s = displacement (maximum height)

Substituting the values, we get:

0 = (20)^2 + 2(-10)s 0 = 400 - 20s 20s = 400 s = 20 m

Therefore, the correct answer is (b) 20 m.

Question 2:

Two wires of the same material have lengths in the ratio 1:2 and radii in the ratio 2:1. The ratio of their resistances is:

(a) 1:2 (b) 2:1 (c) 1:8 (d) 8:1

Solution:

The resistance of a wire is given by the formula:

R = ρl/A

where:

• R = resistance
• ρ = resistivity of the material
• l = length of the wire
• A = cross-sectional area of the wire

Let the lengths of the two wires be l1 and l2, and their radii be r1 and r2, respectively. Then, the ratio of their resistances is:

R1/R2 = (ρl1/πr1^2) / (ρl2/πr2^2) R1/R2 = (l1/l2) * (r2^2/r1^2)

Substituting the given ratios, we get:

R1/R2 = (1/2) * (2^2/1^2) R1/R2 = 2

Therefore, the correct answer is (b) 2:1.

Question 3:

A particle is moving in a circle of radius 1 m with a speed of 2 m/s. The centripetal acceleration of the particle is:

(a) 2 m/s^2 (b) 4 m/s^2 (c) 8 m/s^2 (d) 16 m/s^2

Solution:

The centripetal acceleration of a particle moving in a circle is given by the formula:

a = v^2/r

where:

• a = centripetal acceleration
• v = speed of the particle
• r = radius of the circle

Substituting the given values, we get:

a = (2)^2/1 a = 4 m/s^2

Therefore, the correct answer is (b) 4 m/s^2.

Question 4:

A convex lens has a focal length of 10 cm. An object is placed at a distance of 20 cm from the lens. The image distance is:

(a) 10 cm (b) 20 cm (c) 30 cm (d) 40 cm

Solution:

We can use the lens formula to solve this problem:

1/f = 1/v + 1/u

where:

• f = focal length (10 cm)
• v = image distance
• u = object distance (-20 cm)

Substituting the values, we get:

1/10 = 1/v + 1/(-20) 1/10 = 1/v - 1/20 1/v = 1/10 + 1/20 1/v = 3/20 v = 20/3 cm

Therefore, the correct answer is (a) 10 cm.

Question 5:

A body of mass 1 kg is moving with a velocity of 10 m/s. The kinetic energy of the body is:

(a) 50 J (b) 100 J (c) 150 J (d) 200 J

Solution:

The kinetic energy of a body is given by the formula:

KE = (1/2)mv^2

where:

• KE = kinetic energy
• m = mass of the body
• v = velocity of the body

Substituting the given values, we get:

KE = (1/2)(1)(10)^2 KE = 50 J

Therefore, the correct answer is (a) 50 J.

Chemistry

Question 1:

Which of the following is the correct IUPAC name for the compound CH3CH(OH)CH2CH3?

(a) 2-methylpropan-2-ol (b) 2-butanol (c) 3-butanol (d) 2-methylbutan-2-ol

Solution:

The longest carbon chain contains four carbon atoms, so the parent chain is butane. The hydroxyl group (OH) is attached to the second carbon atom, so the suffix is "-2-ol". There is also a methyl group (CH3) attached to the second carbon atom. Therefore, the correct IUPAC name is 2-methylbutan-2-ol.

Answer: (d) 2-methyl butane-2-ol

Question 2:

What is the major product formed when ethene reacts with HBr?

(a) Bromoethane (b) Ethylene dibromide (c) Bromoethene (d) Ethanol

Solution:

Ethene (CH2=CH2) reacts with HBr in an electrophilic addition reaction. The hydrogen atom of HBr adds to one carbon atom of the double bond, and the bromine atom adds to the other carbon atom. This results in the formation of bromoethane (CH3CH2Br).

Answer: (a) Bromoethane

Question 3:

Which of the following is the strongest acid?

(a) HCl (b) HBr (c) HI (d) HF

Solution:

The acidity of hydrohalic acids increases down the group in the periodic table. This is because the bond strength between hydrogen and the halogen atom decreases, making it easier for the hydrogen ion to be released. Therefore, HI is the strongest acid among the given options.

Answer: (c) HI

Question 4:

What is the oxidation state of sulfur in H2SO4?

(a) +2 (b) +4 (c) +6 (d) +8

Solution:

In H2SO4, the oxidation state of hydrogen is +1 and the oxidation state of oxygen is -2. Let the oxidation state of sulfur be x. Then, the overall charge of the molecule can be represented as:

2(+1) + x + 4(-2) = 0 2 + x - 8 = 0 x = +6

Answer: (c) +6

Question 5:

Which of the following is a colligative property?

(a) Boiling point (b) Freezing point (c) Osmotic pressure (d) All of the above

Solution:

Colligative properties are properties of solutions that depend on the number of solute particles present in the solution, but not on the nature of the solute particles. Boiling point elevation, freezing point depression, and osmotic pressure are all colligative properties.

Answer: (d) All of the above

Question 6:

What is the pH of a solution with a hydrogen ion concentration of 1 x 10^-5 M?

(a) 5 (b) 9 (c) 10 (d) 14

Solution:

The pH of a solution is defined as the negative logarithm of the hydrogen ion concentration:

pH = -log[H+]

In this case, [H+] = 1 x 10^-5 M, so:

pH = -log(1 x 10^-5) = 5

Answer: (a) 5

Question 7:

Which of the following elements has the highest electronegativity?

(a) Fluorine (b) Chlorine (c) Bromine (d) Iodine

Solution:

Electronegativity is the ability of an atom to attract electrons in a chemical bond. Electronegativity increases across a period and decreases down a group in the periodic table. Fluorine is the most electronegative element.

Answer: (a) Fluorine

Question 8:

What is the formula for calculating the molar mass of a compound?

(a) Sum of the atomic masses of all the atoms in the compound (b) Product of the atomic masses of all the atoms in the compound (c) Ratio of the atomic masses of all the atoms in the compound (d) Difference of the atomic masses of all the atoms in the compound

Solution:

The molar mass of a compound is the sum of the atomic masses of all the atoms in the compound.

Answer: (a) Sum of the atomic masses of all the atoms in the compound

Question 9:

Which of the following is an example of a condensation polymer?

(a) Polyethylene (b) Polypropylene (c) Nylon (d) PVC

Solution:

Condensation polymers are formed by the joining of monomers with the elimination of a small molecule, such as water. Nylon is an example of a condensation polymer, formed from the reaction of a diamine and a dicarboxylic acid.

Answer: (c) Nylon

Question 10:

What is the name of the process by which a solid changes directly into a gas?

(a) Melting (b) Boiling (c) Sublimation (d) Condensation

Solution:

Sublimation is the process by which a solid changes directly into a gas without passing through the liquid phase.

Answer: (c) Sublimation

Mathematics

Question 1:

If A = [[1, 2], [3, 4]] and B = [[5, 6], [7, 8]], then A + B is:

(a) [[6, 8], [10, 12]] (b) [[-4, -4], [-4, -4]] (c) [[1, 7], [10, 12]] (d) [[6, 7], [8, 9]]

Solution:

Matrix addition is performed element-wise. So, A + B = [[1+5, 2+6], [3+7, 4+8]] = [[6, 8], [10, 12]]

Answer: (a) [[6, 8], [10, 12]]

Question 2:

The value of the determinant |[2, 3], [4, 5]| is:

(a) -2 (b) 2 (c) 8 (d) 22

Solution:

The determinant of a 2x2 matrix [[a, b], [c, d]] is ad - bc. So, |[2, 3], [4, 5]| = (25) - (34) = 10 - 12 = -2

Answer: (a) -2

Question 3:

If f(x) = x^2 + 2x + 1, then f(2) is:

(a) 5 (b) 9 (c) 10 (d) 11

Solution:

Substitute x = 2 into the function: f(2) = (2)^2 + 2(2) + 1 = 4 + 4 + 1 = 9

Answer: (b) 9

Question 4:

The slope of the line 2x + 3y = 6 is:

(a) 2/3 (b) -2/3 (c) 3/2 (d) -3/2

Solution:

Rewrite the equation in slope-intercept form (y = mx + b), where m is the slope. 3y = -2x + 6 => y = (-2/3)x + 2. Therefore, the slope is -2/3.

Answer: (b) -2/3

Question 5:

The integral of x^2 is:

(a) x^3 + C (b) (x^3)/3 + C (c) 2x + C (d) x^2 + C

Solution:

The power rule of integration states that the integral of x^n is (x^(n+1))/(n+1) + C. So, the integral of x^2 is (x^3)/3 + C.

Answer: (b) (x^3)/3 + C

Question 6:

The derivative of sin(x) is:

(a) cos(x) (b) -cos(x) (c) tan(x) (d) cot(x)

Solution:

The derivative of sin(x) is cos(x).

Answer: (a) cos(x)

Question 7:

The equation of a circle with centre (2, -3) and radius 4 is:

(a) (x-2)^2 + (y+3)^2 = 4 (b) (x+2)^2 + (y-3)^2 = 4 (c) (x-2)^2 + (y+3)^2 = 16 (d) (x+2)^2 + (y-3)^2 = 16

Solution:

The equation of a circle with centre (h, k) and radius r is (x-h)^2 + (y-k)^2 = r^2. So, the equation is (x-2)^2 + (y+3)^2 = 4^2 = 16.

Answer: (c) (x-2)^2 + (y+3)^2 = 16

Question 8:

The value of sin(π/2) is:

(a) 0 (b) 1 (c) -1 (d) √2/2

Solution:

sin(π/2) = 1

Answer: (b) 1

Question 9:

If tan(θ) = 3/4, then cos(θ) is:

(a) 3/5 (b) 4/5 (c) 5/3 (d) 5/4

Solution:

Since tan(θ) = opposite/adjacent = 3/4, we can consider a right triangle with opposite side 3 and adjacent side 4. The hypotenuse is √(3^2 + 4^2) = 5. cos(θ) = adjacent/hypotenuse = 4/5.

Answer: (b) 4/5

Question 10:

The limit of (sin(x)/x) as x approaches 0 is:

(a) 0 (b) 1 (c) ∞ (d) -∞

Solution:

This is a standard limit: lim (x->0) sin(x)/x = 1

Answer: (b) 1

Biology

Question 1:

Which of the following is NOT a characteristic of all living organisms?

(a) Reproduction (b) Metabolism (c) Movement (d) Consciousness

Solution:

While most living organisms exhibit movement, it's not a universal characteristic. For example, plants are living organisms but generally don't exhibit locomotion in the same way animals do. Reproduction, metabolism, and consciousness (responsiveness to stimuli) are considered fundamental characteristics of life.

Answer: (c) Movement

Question 2:

The primary site of photosynthesis in plants is:

(a) Roots (b) Stems (c) Leaves (d) Flowers

Solution:

Leaves contain chloroplasts, which are the organelles where photosynthesis takes place. Their large surface area and arrangement maximize light absorption.

Answer: (c) Leaves

Question 3:

Which of the following is the most inclusive (broadest) taxonomic category?

(a) Genus (b) Species (c) Kingdom (d) Family

Solution:

The taxonomic hierarchy proceeds from broadest to most specific: Kingdom, Phylum, Class, Order, Family, Genus, Species.

Answer: (c) Kingdom

Question 4:

Which of these is a vestigial structure in humans?

(a) Heart (b) Appendix (c) Brain (d) Lungs

Solution:

A vestigial structure has lost its original function during evolution. The appendix is considered a vestigial organ in humans.

Answer: (b) Appendix

Question 5:

The process of meiosis results in:

(a) Two identical daughter cells (b) Four genetically different daughter cells (c) Two genetically different daughter cells (d) Four identical daughter cells

Solution:

Meiosis is a type of cell division that reduces the number of chromosomes by half and produces gametes (sex cells). It results in four genetically different haploid daughter cells.

Answer: (b) Four genetically different daughter cells

Question 6:

Which gas is most abundant in Earth's atmosphere?

(a) Oxygen (b) Carbon Dioxide (c) Nitrogen (d) Hydrogen

Solution:

Nitrogen makes up approximately 78% of Earth's atmosphere.

Answer: (c) Nitrogen

Question 7:

Which of the following is a DNA base NOT found in RNA?

(a) Adenine (b) Guanine (c) Cytosine (d) Thymine

Solution:

Thymine is replaced by Uracil in RNA.

Answer: (d) Thymine

Question 8:

The basic structural and functional unit of life is:

(a) Tissue (b) Organ (c) Cell (d) Organ System

Solution:

The cell is the fundamental unit of life. All living organisms are composed of cells.

Answer: (c) Cell

Question 9:

Which of the following is an example of a monosaccharide?

(a) Sucrose (b) Lactose (c) Glucose (d) Starch

Solution:

Glucose is a monosaccharide (a simple sugar). Sucrose and lactose are disaccharides, and starch is a polysaccharide.

Answer: (c) Glucose

Question 10:

Which of these is responsible for carrying oxygen in the blood?

(a) Hemoglobin (b) Plasma (c) Platelets (d) White blood cells

Solution:

Haemoglobin, a protein found in red blood cells, is responsible for transporting oxygen throughout the body.

Answer: (a) Hemoglobin