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BITSAT 18th Sept 2020 (Slot 1, 2) Exam & Question Paper Analysis (Available), Answer Key, Solutions

Diksha Sharma
Diksha SharmaPublished On: September 21, 2020 | BITSAT

Day 3 of the BITSAT 2020 exam has been conducted on September 18, 2020, in two slots. Check BITSAT 18th September Slot 1 & 2 exam analysis, answer key, and solutions here.


BITSAT 2020 Day 3 exam has been conducted on September 18th, 2020 in two slots. Proper COVID-19 safety measures were taken at the exam centres for students. As per the Day 2 exam analysis of BITSAT, while the slot 1 exam was moderate to difficult, the slot 2 exam was quite difficult. The following article will overview the BITSAT 18th September 2020 exam analysis along with the answer keys and solutions. Questions are being added. Scroll down to check.

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BITSAT 18th Sept 2020 Exam Analysis (Slot 1, 2)

The BITSAT 18th Sept 2020 exam analysis for both slot 1 and 2 is provided in the table below. Overall, some students expressed that the question paper is slightly tough than JEE Main. However, NCERT syllabus dominated the question paper.


Slot 1

Slot 2

Overall Level of Difficulty

Moderate to DifficultTBA

Physics Difficulty Level


Chemistry Difficulty Level

Easy to ModerateTBA

Mathematics Difficulty Level

Moderate to DifficultTBA

Topics with More Weightage in Physics

  • Wave Optics
  • Thermodynamics
  • Heat Transfer
  • Modern Physics

Topics with More Weightage in Chemistry

  • Electrochemistry
  • D-Block & F-Block
  • Biomolecules

Topics with More Weightage in Mathematics

  • Trigonometric Equations
  • Probability
  • Sequence & Series
  • Sets, Relations and Functions

Topics with More Weightage in English

  • Sentence Correction

Good Score


BITSAT 18th Sept 2020 Question Paper & Answer Key (Memory-Based)

We will be sharing the memory-based questions of the students who have appeared for the BITSAT exam here. If you remember some questions, please send them to

BITSAT 18th Sept 2020 Shift 2 Questions (Memory-Based)

The memory-based questions of the BITSAT 18th September 2020 exam can be checked below. The following questions have been shared by the students who appeared for the BITSAT exam. Stay updated for the solutions!


 If a circle of 7cm diameter is drawn and a chord of 6cm is drawn, then find the max area of the quadrilateral inscribed in a circle formed by using 6cm chord as diagonal of the quadrilateral

Derivative of cosx^2
Hybridisation of PCl5Dimensions of compressibility 
Dimensions of Young's modulusA swimmer coming out from a pool is covered with a film of water then calculate the internal energy. 
Boiling point order of hydrides of 14th groupIntegral of tan(logx)/x
Integral of sin^2x/(sin^2x+cos^2x) limits from 0 to π/2

Unit of compressibility is ?

BITSAT 17th Sept 2020 Questions

List of Popular B.Tech Colleges for Direct B.Tech Admission

The below table enlists the popular B.Tech colleges which offer direct admission without BITSAT score:

University of Engineering & Management (UEM) – Jaipur

Jaipur Engineering College

Jagaran Lakecity University - Bhopal

Lovely Professional University

Sage University, Indore

CMR Institute of Technology, Hyderabad

Bharat Institute of Technology, Meerut

Roorkee Engineering College, Roorkee

JECRC University - Jaipur

OM Dayal Group of Institutions, Howrah

For the latest updates related to BITSAT, stay tuned to CollegeDekho.

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Related Questions

My daughter has passed 12th with 64% in Science PCM and we belong to OBC category. Can you help me with the admission details for B.Tech in ELECTRONIC & COMMUNICATIONS?

-Umesh Vasant KholamkarUpdated on August 30, 2021 11:15 AM
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Diksha Sharma, Student / Alumni

You can take admission to B.Tech Electronics & Communication program for which the minimum eligibility is to pass 12th in Science with 50% minimum aggregate. However, since you belong to OBC category, you will have 5% relaxation in the minimum aggregate criteria. This means you will have to acquire a minimum aggregate of 45%.

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I want to know about the Chemical Engineering course, colleges & fee structure. I have completed my 10+2.

-vennapusa sharath kumar reddyUpdated on August 30, 2021 10:51 AM
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Diksha Sharma, Student / Alumni

Dear Student,

If you have completed your 10+2 in Science with Physics & Mathematics as the main subjects, then you are eligible for admission to B.Tech in Chemical Engineering. The course is of a total of 4 year's duration which is divided into a total of 8 semesters. If you want to get the complete details related to the course such as colleges, fees, admission process, etc., you can check the B.Tech Chemical Engineering Course Details.

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What is average placements in CSE and IT at CGC, Landran? Also, is the interview for placement difficult for students?

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Diksha Sharma, Student / Alumni

Dear Student,

The Computer Science Engineering and Information Technology at Chandigarh Group of Colleges, Landran, Mohali, is good. The students are provided placement opportunities in some of the top-notch companies in India such as Wipro, TCS, Microsoft, Capgemini, etc. The lowest package for CSE and IT at CGC placement is 3 LPA, the average package is 6-8 LPA and the highest package is 22 LPA.

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