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JEE Main 2019 Normalisation Process: Check How to Calculate Scores

Published: | January 23, 2019
JEE Main 2019 Normalisation Process: Check How to Calculate Scores

For the first time, percentile-based normalisation procedure has been incorporated in JEE Main 2019 exam. Check details about JEE Main 2019 normalisation procedure based on percentile score and process to calculate JEE Main 2019 score here.

JEE Main January 2019 results have been announced. For the first time, percentile-based scoring mechanism/ normalisation procedure was incorporated in JEE Main. 15 students scored 100/100 in JEE Main January 2019. NTA (National Testing Agency) has published the percentile-based normalisation procedure for JEE Main 2019. The normalisation procedure of JEE Main will help students to calculate his/ her score in JEE Main exam. The percentile-based normalisation procedure enables NTA to prepare ranks for JEE Main. Students can check the complete process of JEE Main 2019 percentile-based normalisation procedure that is used to calculate the score and allot ranks below. You can also apply for B.Tech courses in India basis your score by clicking here.

Importance of Normalisation Procedure based on Percentile Score in JEE Main 2019

NTA conducts JEE Main exam on multiple days with two sessions per day. In each session, students will get different sets of question papers, and the difficulty level may not be the same across all sets of question papers. Despite NTA’s efforts to maintain similar difficulty level across all sessions of JEE Main exam, some of the candidates may attempt a tougher question paper when compared to other sets. Therefore, these students end up getting lower marks in JEE Main than the candidates who attempted an easier question paper.

In order to provide justice to the candidates who attempted a difficult or tough question paper, NTA uses normalisation procedure based on percentile score so that the candidates are neither benefitted nor disadvantaged. The true merit of the candidate can be identified through normalisation procedure. Therefore, NTA compiles JEE Main scores for multiple session question papers through normalisation procedure based on percentile score.

What is Normalisation Procedure?

Normalisation procedure is a popular practice of comparing candidates’ score across multiple sessions question papers. Percentile equivalence is used for normalisation across all sections of the exam. Normalisation procedure is incorporated in all popular national and state-level entrance exams.

JEE Main Percentile Score

Percentile scores indicate the relative performance of all students who appear for JEE Main exam. The marks obtained by students in JEE Main shall be transformed into a scale ranging from 100 to 0 for each JEE Main exam session of examines.

For example, Percentile scores denote the percentage of students who scored equal or below marks than the student who scored highest marks in a particular session of JEE Main exam. The marks of these students will be transformed into a percentile. As percentile score is denoted for each session of JEE Main, the topper of each session exam will get 100 percentile in JEE Main.

The percentile score is the normalised score for the JEE Main exam, and it is used to prepare the merit/ rank list of JEE Main. In order to avoid inequality or bunching effect and reduce ties, JEE Main percentile scores are calculated up to 7 decimal places.

Procedure to Calculate JEE Main Percentile Score

The following are required to calculate JEE Main percentile score –

  • Total number of candidates appeared in a particular session of JEE Main exam
  • A highest raw score of a candidate in that session of JEE Main

Note: The percentile score secured by a candidate will be different from the raw score. Percentile score is not similar to the percentage of marks obtained by a candidate.

JEE Main percentile score is calculated as per the formula is given below –

100 multiplied by total number of candidates appeared in a particular session of JEE Main exam with the raw score less than or equal to the candidate who scored highest raw score divided by the Total number of candidates appeared in that particular session.

Example 1

In JEE Main, 4 marks are awarded for each correct answer while 1 mark is deducted for each wrong answer. JEE Main exam will have 90 questions for 360 marks. The marks secured by candidates out of 360 shall not be considered for preparing ranks. The marks secured by candidates will be transformed into a scale ranging from 100 to 0 through normalisation procedure. Check the example below –

Let us assume that the JEE Main exam was conducted in four sessions and the highest and lowest score of the candidates is as follows –

Session

Highest Raw Score Secured by a Student

Total Number of Candidates Appeared for the Exam

Total Number of Candidates who Scored Equal to or Less than the highest raw score of a candidate

Percentile of the Student who Scored Highest Marks

Explanation (Apply the Above Formula)

Session 1

335

28,012

28,012

100 Percentile

(28012/28012) X 100 = 100

Session 2

346

32,541

32,541

100 Percentile

(32541/32541) X 100 = 100

Session 3

331

41,326

41,326

100 Percentile

(41326/41326) X 100 = 100

Session 4

332

40,603

40,603

100 Percentile

(40603/40603) X 100 = 100

From the above example, it is clear that a candidate who secures the highest raw score in each session will get 100 percentile.

Example 2:

In this example, let us check the raw scores and percentile of students in a particular session of JEE Main -

Name of the Candidate

Raw Score Secured by the Candidate

Candidates Scored Less raw score than the candidate

Total Number of Candidates Appeared for the Exam

Percentile of the Student

Explanation

A

335 out of 360

28,000

28,012

99.9571612

(28000/28012) X 100 = 99.9571612

B

330 out of 360

27,012

28,012

96.4301013

(27012/28012) X 100 = 96.4301013

C

310 out of 360

20,000

28,012

71.3979722

(20000/28012) X 100 = 71.3979722

D

270 out of 360

16,588

28,012

59.2174782

(16588/28012) X 100 = 59.2174782

X

230 out of 360

13,999

28,012

49.9750107

(13999/28012) X 100 = 49.9750107

Y

99 out of 360

6,700

28,012

23.9183207

(6700/28012) X 100 = 23.9183207

Z

58 out of 360

400

28,012

1.42795944

(400/28012) X 100 = 1.42795944

Also Read: Engineering Colleges in India that Do Not Require JEE Main Score for Admission

JEE Main Tie-Breaking Rules

If two or more candidates obtain the same percentile score in a session of JEE Main, the following rules shall be applied to determine the order of the candidate in the merit list –

  • Candidates scoring highest percentile in Mathematics shall be considered
  • In case if there is a tie after incorporating the above rule, highest marks obtained by candidates in Physics shall be considered
  • If the tie still persists, highest percentile secured by candidates in Chemistry shall be considered
  • If the tie still persists, the candidate with older in age shall be considered

Preparation of JEE Main Results for Each Session

NTA prepares the results for each session by considering the following components –

  • A raw score of the candidates, i.e., total marks scored by candidates out of 360.
  • Percentile score secured by the candidates, i.e., overall percentile, percentile scores in mathematics, Physics and Chemistry.

The percentile scores are prepared as per the examples mentioned above. The similar formula applies for denoting percentile scores for each subject.

JEE Main Ranking System 2019

The JEE Main percentile score of all sessions will be calculated separately and the raw score of candidates in 3 subjects (Mathematics, Physics and Chemistry) and overall raw score shall be considered for preparing the overall rank list/ merit list. The final NTA score is prepared on the basis of overall raw score and raw score in three subjects.

You can check estimated JEE Main 2019 opening and closing ranks for more clarity. You can also check a detailed comparison between JEE Main Marks vs Ranks here.

Candidates who appeared for JEE Main January 2019 exam can also appear for JEE Main April 2019 exam to improve the score. The best percentile score between the two exams shall be considered for preparing the overall rank list/ merit list.

Also Read: Analysis – WBJEE Marks vs Ranks

We hope that the above article has clarified all your doubts about JEE Main normalisation procedure based on percentile score.

For the latest JEE Main 2019 updates, stay tuned to CollegeDekho.

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